Question
In: Math
Descriptives Current stress level N Mean Std. Deviation Std. Error 95% Confidence Interval for Mean Minimum...
|
Descriptives |
||||||||
|
Current stress level |
||||||||
|
N |
Mean |
Std. Deviation |
Std. Error |
95% Confidence Interval for Mean |
Minimum |
Maximum |
||
|
Lower Bound |
Upper Bound |
|||||||
|
Psychologist |
5 |
1.0000 |
1.73205 |
.77460 |
-1.1506 |
3.1506 |
.00 |
4.00 |
|
Doctor |
5 |
5.0000 |
2.23607 |
1.00000 |
2.2236 |
7.7764 |
2.00 |
8.00 |
|
Lawyer |
5 |
6.0000 |
1.87083 |
.83666 |
3.6771 |
8.3229 |
4.00 |
9.00 |
|
Total |
15 |
4.0000 |
2.87849 |
.74322 |
2.4059 |
5.5941 |
.00 |
9.00 |
|
Test of Homogeneity of Variances |
|||
|
Current stress level |
|||
|
Levene Statistic |
df1 |
df2 |
Sig. |
|
.170 |
2 |
12 |
.845 |
|
ANOVA |
|||||
|
Current stress level |
|||||
|
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
|
Between Groups |
70.000 |
2 |
35.000 |
9.130 |
.004 |
|
Within Groups |
46.000 |
12 |
3.833 |
||
|
Total |
116.000 |
14 |
|||
|
*. The mean difference is significant at the 0.05 level. |
1. Write up the results from this analysis using APA format. Make sure you include each group mean (and SD) exam score, the correct F stat with the correct degrees of freedom and p-value, decision regarding the null, and the follow-up comparisons (if necessary). Use the example in the SPSS ANOVA lecture to help guide you. [3 points]
Solutions
milcah answered 3 months agoRelated Solutions
3.For a 95% confidence level, with a standard deviation equal to 25 and a sampling error...
3.For a 95% confidence level, with a standard deviation equal to
25 and a sampling error of 5, calculate the sample size
a.99.96
b.61.47
c.96.04
d.75.00
Find the margin of error for a 95% confidence interval (nearest hundredths) of the mean test...
Find the margin of error for a 95% confidence interval (nearest
hundredths) of the mean test score of Statistics students at
Clayton State University given the following sample data scores: 87
85 56 82 67 77 73 71 90 74 76 79 81 84
Find a 99% confidence interval estimate (nearest hundredth)
using the data in #12.
The height (in inches) of males in the United States is believed
to be Normally distributed, with mean µ. The average height of...
2. What is the sample size, n, for a 95% confidence interval on the mean, if...
2. What is the sample size, n, for a 95% confidence interval on
the mean, if we know that the process’ standard error is 3.2 units,
and we want to allow at most 1.0 units for our error?
3. Let’s say that you just randomly pulled 32 widgets from your
production line and you determined that you need a sample size of
46 widgets, However, you get delayed in being able to pull another
bunch of widgets from the line...
Group Statistics gender N Mean Std. Deviation Std. Error Mean salary male 47 32442.23 3117.026 454.665...
Group
Statistics
gender
N
Mean
Std. Deviation
Std. Error Mean
salary
male
47
32442.23
3117.026
454.665
female
47
33920.57
3824.284
557.829
Independent
Samples Test
Levene's Test for
Equality of Variances
t-test for Equality of
Means
F
Sig.
t
df
Sig. (2-tailed)
Mean Difference
Std. Error
Difference
95% Confidence
Interval of the Difference
Lower
Upper
salary
Equal variances
assumed
.964
.329
-2.054
92
.043
-1478.340
719.648
-2907.624
-49.057
Equal variances not
assumed
-2.054
88.404
.043
-1478.340
719.648
-2908.399
-48.282
Here we...
Group Statistics Group N Mean Std. Deviation Std. Error Mean Scores male 50 49.7200 10.40220 1.47109...
Group
Statistics
Group
N
Mean
Std. Deviation
Std. Error Mean
Scores
male
50
49.7200
10.40220
1.47109
female
50
31.5800
11.59009
1.63909
Independent
Samples Test
Levene's Test for
Equality of Variances
t-test for Equality of
Means
F
Sig.
t
df
Sig. (2-tailed)
Mean Difference
Std. Error
Difference
95% Confidence
Interval of the Difference
Lower
Upper
Scores
Equal variances
assumed
.519
.473
8.236
98
.000
18.14000
2.20243
13.76934
22.51066
Equal variances not
assumed
8.236
96.876
.000
18.14000
2.20243
13.76871
22.51129
Imagine that...
Find the mean, standard deviation, 80%, 95%, and 99% confidence intervals, and margin of error for...
Find the mean, standard deviation,
80%, 95%, and 99% confidence intervals, and margin of error for
those intervals. Show all work.
$32,096
$29,716
$29,227
$27,209
$22,794
$19,306
$19,238
$19,164
18,994
$18,329
$17,978
$17,626
$16,823
$16,709
$15,967
$15,921
$15,908
$15,905
$15,638
$15,629
$14,414
$14,229
$14,137
$14,051
$13,907
$13,776
$13,281
$12,739
$12,300
$11,994
$11,262
$11,112
$10,984
$10,824
$10,823
$10,448
$10,081
$9,883
$9,668
$9,663
$9,337
$8,855
$8,741
$8,596
$8,385
$7,204
$7,072
$6,503
$5,653
$4,602
The 95% confidence interval for the mean, calculated from a sample of size n = 25...
The 95% confidence interval for the mean, calculated from a
sample of size n = 25 is 2.233163 ≤ μ ≤ 3.966837 . Determine the
sample mean X ¯ = (round to the first decimal place). Assuming that
the data is normally distributed, determine the sample standard
deviation s = (round to the first decimal place)
14. A researcher estimates the 95% Confidence Interval for a sample (n=100) with a mean of...
14. A researcher estimates the 95% Confidence Interval for a
sample (n=100) with a mean of M=3. The population mean and standard
deviation are known as 2.5±2 (µ±σ). What is the upper confidence
limit for this interval? A) 0.392 B) 1.96 C) 2.608 D) 3.392 E)
There is not enough information to answer this question.
At a confidence level of 95% a confidence interval for a population proportion is determined to...
At a confidence level of 95% a confidence interval for a
population proportion is determined to be 0.65 to 0.75. If the
sample size had been larger and the estimate of the population
proportion the same, this 95% confidence interval estimate as
compared to the first interval estimate would be
A. the same
B. narrower
C. wider
At a confidence level of 95% a confidence interval for a population proportion is determined to...
At a confidence level of 95% a confidence interval for a
population proportion is determined to be 0.65 to 0.75. If the
sample size had been larger and the estimate of the population
proportion the same, this 95% confidence interval estimate as
compared to the first interval estimate would be
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