In: Finance
Use the after-tax IRR method to evaluate the following three alternatives for MACRS 3-year property, and offer a recommendation. The after-tax MARR is 25%, the project life is 5 years, and the firm has a combined incremental tax rate of 45%.
Formula sheet
A | B | C | D | E | F | G | H | I | J |
2 | |||||||||
3 | |||||||||
4 | Project Life | 5 | years | ||||||
5 | Tax Rate | 0.45 | |||||||
6 | MARR | 0.25 | |||||||
7 | |||||||||
8 | Cash Flow Calculation for Altenative A: | ||||||||
9 | |||||||||
10 | Depreciation follows MACRS 3 year convention. | ||||||||
11 | Tax basis of the equipment (B) | 14000 | |||||||
12 | |||||||||
13 | Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | ||||
14 | MACRS 3 Year depreciation rate (rt) | 0.3333 | 0.4445 | 0.1481 | 0.0741 | 0 | |||
15 | Depreciation (B*rt) | =$D$11*E14 | =$D$11*F14 | =$D$11*G14 | =$D$11*H14 | =$D$11*I14 | |||
16 | Book Value | =D11 | =D16-E15 | =E16-F15 | =F16-G15 | =G16-H15 | =H16-I15 | ||
17 | |||||||||
18 | Calculation of after tax net cash flow from the sale of the asset at the end of year 5: | ||||||||
19 | |||||||||
20 | Proceed from sale of machine | 5000 | |||||||
21 | Book Value of Machine at the end of Year 5 | =I16 | |||||||
22 | Gain or Loss on sale | =Proceed From Sale - Book value at the end of sale | |||||||
23 | =D20-D21 | ||||||||
24 | |||||||||
25 | Tax rate | =D5 | |||||||
26 | Gain or Loss on sale | =D23 | |||||||
27 | Tax on Gain & Loss | =D26*D25 | |||||||
28 | Net Proceed from Sale of assets at the end | =Proceed from Sale - Tax Expense on gain or loss | |||||||
29 | =D20-D27 | ||||||||
30 | |||||||||
31 | Hence after-tax net cash flow from the sale of the asset | =D29 | |||||||
32 | |||||||||
33 | Cash Flow can be calculated as follows: | ||||||||
34 | Year | 0 | 1 | 2 | 3 | 4 | 5 | ||
35 | Investment | =-D11 | |||||||
36 | Annual cost | -2500 | -2500 | -2500 | -2500 | -2500 | |||
37 | Depreciation | =-E15 | =-F15 | =-G15 | =-H15 | =-I15 | |||
38 | Operating Income Before Tax (EBIT) | =SUM(E36:E37) | =SUM(F36:F37) | =SUM(G36:G37) | =SUM(H36:H37) | =SUM(I36:I37) | |||
39 | Tax expense | =-E38*$D$5 | =-F38*$D$5 | =-G38*$D$5 | =-H38*$D$5 | =-I38*$D$5 | |||
40 | After Tax operating income (EBIT*(1-T)) | =E38+E39 | =F38+F39 | =G38+G39 | =H38+H39 | =I38+I39 | |||
41 | Add Depreciation | =-E37 | =-F37 | =-G37 | =-H37 | =-I37 | |||
42 | Net Operating Cash Flow | =E40+E41 | =F40+F41 | =G40+G41 | =H40+H41 | =I40+I41 | |||
43 | Net cash flow from the sale of the asset | =D31 | |||||||
44 | Net Cash Flow for Alt A | =D35 | =E42+E43 | =F42+F43 | =G42+G43 | =H42+H43 | =I42+I43 | ||
45 | |||||||||
46 | Cash Flow Calculation for Altenative B: | ||||||||
47 | |||||||||
48 | Depreciation follows MACRS 3 year convention. | ||||||||
49 | Tax basis of the equipment (B) | 18000 | |||||||
50 | |||||||||
51 | Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | ||||
52 | MACRS 3 Year depreciation rate (rt) | 0.3333 | 0.4445 | 0.1481 | 0.0741 | 0 | |||
53 | Depreciation (B*rt) | =$D$54*E52 | =$D$54*F52 | =$D$54*G52 | =$D$54*H52 | =$D$54*I52 | |||
54 | Book Value | =D49 | =D54-E53 | =E54-F53 | =F54-G53 | =G54-H53 | =H54-I53 | ||
55 | |||||||||
56 | Calculation of after tax net cash flow from the sale of the asset at the end of year 5: | ||||||||
57 | |||||||||
58 | Proceed from sale of machine | 10000 | |||||||
59 | Book Value of Machine at the end of Year 5 | =I54 | |||||||
60 | Gain or Loss on sale | =Proceed From Sale - Book value at the end of sale | |||||||
61 | =D58-D59 | ||||||||
62 | |||||||||
63 | Tax rate | =D5 | |||||||
64 | Gain or Loss on sale | =D61 | |||||||
65 | Tax on Gain & Loss | =D64*D63 | |||||||
66 | Net Proceed from Sale of assets at the end | =Proceed from Sale - Tax Expense on gain or loss | |||||||
67 | =D58-D65 | ||||||||
68 | |||||||||
69 | Hence after-tax net cash flow from the sale of the asset | =D67 | |||||||
70 | |||||||||
71 | Cash Flow can be calculated as follows: | ||||||||
72 | Year | 0 | 1 | 2 | 3 | 4 | 5 | ||
73 | Investment | =-D49 | |||||||
74 | Annual cost | -1000 | -1000 | -1000 | -1000 | -1000 | |||
75 | Depreciation | =-E53 | =-F53 | =-G53 | =-H53 | =-I53 | |||
76 | Operating Income Before Tax (EBIT) | =SUM(E74:E75) | =SUM(F74:F75) | =SUM(G74:G75) | =SUM(H74:H75) | =SUM(I74:I75) | |||
77 | Tax expense | =-E76*$D$5 | =-F76*$D$5 | =-G76*$D$5 | =-H76*$D$5 | =-I76*$D$5 | |||
78 | After Tax operating income (EBIT*(1-T)) | =E76+E77 | =F76+F77 | =G76+G77 | =H76+H77 | =I76+I77 | |||
79 | Add Depreciation | =-E75 | =-F75 | =-G75 | =-H75 | =-I75 | |||
80 | Net Operating Cash Flow | =E78+E79 | =F78+F79 | =G78+G79 | =H78+H79 | =I78+I79 | |||
81 | Net cash flow from the sale of the asset | =D69 | |||||||
82 | Net Cash Flow for Alt B | =D73 | =E80+E81 | =F80+F81 | =G80+G81 | =H80+H81 | =I80+I81 | ||
83 | |||||||||
84 | |||||||||
85 | Cash Flow Calculation for Altenative C: | ||||||||
86 | |||||||||
87 | Depreciation follows MACRS 3 year convention. | ||||||||
88 | Tax basis of the equipment (B) | 10000 | |||||||
89 | |||||||||
90 | Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | ||||
91 | MACRS 3 Year depreciation rate (rt) | 0.3333 | 0.4445 | 0.1481 | 0.0741 | 0 | |||
92 | Depreciation (B*rt) | =$D$93*E91 | =$D$93*F91 | =$D$93*G91 | =$D$93*H91 | =$D$93*I91 | |||
93 | Book Value | =D88 | =D93-E92 | =E93-F92 | =F93-G92 | =G93-H92 | =H93-I92 | ||
94 | |||||||||
95 | |||||||||
96 | Cash Flow can be calculated as follows: | ||||||||
97 | Year | 0 | 1 | 2 | 3 | 4 | 5 | ||
98 | Investment | =-D88 | |||||||
99 | Annual cost | -5000 | -5000 | -5000 | -5000 | -5000 | |||
100 | Depreciation | =-E92 | =-F92 | =-G92 | =-H92 | =-I92 | |||
101 | Operating Income Before Tax (EBIT) | =SUM(E99:E100) | =SUM(F99:F100) | =SUM(G99:G100) | =SUM(H99:H100) | =SUM(I99:I100) | |||
102 | Tax expense | =-E101*$D$5 | =-F101*$D$5 | =-G101*$D$5 | =-H101*$D$5 | =-I101*$D$5 | |||
103 | After Tax operating income (EBIT*(1-T)) | =E101+E102 | =F101+F102 | =G101+G102 | =H101+H102 | =I101+I102 | |||
104 | Add Depreciation | =-E100 | =-F100 | =-G100 | =-H100 | =-I100 | |||
105 | Net Operating Cash Flow | =E103+E104 | =F103+F104 | =G103+G104 | =H103+H104 | =I103+I104 | |||
106 | Net cash flow from the sale of the asset | 0 | |||||||
107 | Net Cash Flow for Alt C | =D98 | =E105+E106 | =F105+F106 | =G105+G106 | =H105+H106 | =I105+I106 | ||
108 | |||||||||
109 | Calculation of Incremental IRR A-C: | ||||||||
110 | |||||||||
111 | Year | 0 | 1 | 2 | 3 | 4 | 5 | ||
112 | Net Cash Flow for Alt A | =D44 | =E44 | =F44 | =G44 | =H44 | =I44 | ||
113 | Net Cash Flow for Alt C | =D107 | =E107 | =F107 | =G107 | =H107 | =I107 | ||
114 | Incremental Cash Flow A-C | =D112-D113 | =E112-E113 | =F112-F113 | =G112-G113 | =H112-H113 | =I112-I113 | ||
115 | Incremental IRR A-C | =IRR(D114:I114) | |||||||
116 | |||||||||
117 | Hence Incremental IRR A-C | =D115 | |||||||
118 | |||||||||
119 | |||||||||
120 | Calculation of Incremental IRR B-A: | ||||||||
121 | |||||||||
122 | Year | 0 | 1 | 2 | 3 | 4 | 5 | ||
123 | Net Cash Flow for Alt B | =D82 | =E82 | =F82 | =G82 | =H82 | =I82 | ||
124 | Net Cash Flow for Alt A | =D44 | =E44 | =F44 | =G44 | =H44 | =I44 | ||
125 | Incremental Cash Flow B-A | =D123-D124 | =E123-E124 | =F123-F124 | =G123-G124 | =H123-H124 | =I123-I124 | ||
126 | Incremental IRR B-A | =IRR(D125:I125) | |||||||
127 | |||||||||
128 | Hence Incremental IRR B-A | =D126 | |||||||
129 | |||||||||
130 | |||||||||
131 | If the incremental IRR is higher than the required rate of return then the higher cost alternative should be selected. | ||||||||
132 | |||||||||
133 | Given the following data: | ||||||||
134 | Incremental IRR A-C | =D117 | |||||||
135 | Incremental IRR B-A | =D128 | |||||||
136 | |||||||||
137 | Since C is the lowest cost alternative and alternative A is the next lowest cost alternative, | ||||||||
138 | therefore incremental IRR A-C is to be considered first. | ||||||||
139 | |||||||||
140 | Since incremental IRR A-C is 43.81% which is higher than MARR, | ||||||||
141 | therefore alternative A should be selected and alternative C should be removed from the analysis. | ||||||||
142 | |||||||||
143 | Next incremental IRR of the B with respect to A needs to be considered. | ||||||||
144 | Since incremental IRR B-A is 28.26% which is higher than MARR, | ||||||||
145 | therefore alternative B should be selected and alternative A should be removed from the analysis. | ||||||||
146 | |||||||||
147 | Thus alternative B should be selected. | ||||||||
148 |