Question

Python HW with Jupyter Notebook

1. Declare a variable named DATA as a dictionary object. Assign the set of key/value pairs shown below.
2. Create a function named iter_dict_funky_sum() that takes one dictionary argument.   
3. Declare a running total integer variable.
4. Extract the key/value pairs from DATA simultaneously in a loop. Do this with just one for loop and no additional forms of looping.
5. Assign and append the product of the value minus the key to the running total variable.
6. Return the funky total.

Dictionary Data

DATA = {
    2: 7493945,
    76: 4654320,
    3: 4091979,
    90: 1824881,
    82: 714422,
    45: 1137701,
    10: 374362,
    0: 326226,
    -15: 417203,
    -56: 333525,
    67: 323451,
    99: 321696,
    21: 336753,
    -100: 361237,
    55: 1209714,
    5150: 1771800,
    42: 4714011,
    888: 14817667,
    3500: 13760234,
    712: 10903322,
    7: 10443792,
    842: 11716264,
    18584: 10559923,
    666: 9275602,
    70: 11901200,
    153: 12074784,
    8: 4337229
}

Expected Output

>>> iter_dict_funky_sum(DATA)
140166242

Answer 1

Code:

# d is the input dictionary
def iter_dict_funky_sum(d):
  total = 0
  for key,value in d.items(): # iterate through dictionary in a single loop
    total = total + (value - key) # append to total value - key
  return total # return total

DATA = {
    2: 7493945,
    76: 4654320,
    3: 4091979,
    90: 1824881,
    82: 714422,
    45: 1137701,
    10: 374362,
    0: 326226,
    -15: 417203,
    -56: 333525,
    67: 323451,
    99: 321696,
    21: 336753,
    -100: 361237,
    55: 1209714,
    5150: 1771800,
    42: 4714011,
    888: 14817667,
    3500: 13760234,
    712: 10903322,
    7: 10443792,
    842: 11716264,
    18584: 10559923,
    666: 9275602,
    70: 11901200,
    153: 12074784,
    8: 4337229
}
iter_dict_funky_sum(DATA)

code screenshot:

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Code alongs with comment and screenshot has been added.