Please comment, exactly how this program works? #include <stdio.h> int main() { int i,j; int a[1000];...

Please comment, exactly how this program works?

#include <stdio.h>

int main()
{
int i,j;
int a[1000];

for(i=0;i<1000;i++)
a[i]=1;

for(i=2;i<1000;i++)
{
if(a[i]==1){
for(j=i+1;j<1000;j++)
{if(j%(i)==0)
a[j]=0;
}
}
}
printf("print numbers are:\n");
for(i=2;i<=1000;i++)
if(a[i]==1)
printf("%d, ",i);
}

Expert Solution

Code With Comments:

#include <stdio.h>

int main()
{
   int i,j;//This line intialize the variables i and j
   int a[1000];//This line intialize the array with the length of 1000 elements
   for(i=0;i<1000;i++)//This loop used to assign 1 to the all the indexs in the array
       a[i]=1;
   for(i=2;i<1000;i++)//This loop runs from the second index position of the array to the end of the array
   {
       /*
       This below if condition checks weather the a[i]==1 or not if a[i]==1 then it runs the below loop else loop not executed
       */
       if(a[i]==1){
           /*
           Suppose assume that if i=2 the below loop runs from the index position i+1 to 999 means 3 to 999
           */
           for(j=i+1;j<1000;j++)
           {
               /*This condition checks if j is divisible by I or not if yes then a[j]=0
                   in the above we have assumed that i=2 and now in the first iteration j=3 it checks 3%2==0
                   or not if yes then a[j] means a[3]=0
               */
               if(j%(i)==0)
               a[j]=0;
           }
       }
   }
   printf("print numbers are:\n");
   /*
   The below loop runs from the 2 to 1000 and prints the index position of the array a if the value of index position is 1
   */
   for(i=2;i<=1000;i++)
   if(a[i]==1)
   printf("%d, ",i);
}

Code snippet:

venereology answered 1 month ago

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