Question

In: Math

For a parallel structure of identical components, the system can succeed if at least one of...

For a parallel structure of identical components, the system can succeed if at least one of the components succeeds. Assume that components fall independently of each other and that each component has a 0.21 probability of failure.

(A) Would it be unusual to observe one component fail? Two components?
Fill in blanks:
It (would,would not) be unusual to observe one component fail, since the probability that one component fails,___is, (less,greater) than 0.05. It (would not, would) be unusual to observe two components fail, since the probability that two components fail ____, is (greater,less) than 0.05

Solutions

Expert Solution

answrer:

  • Given that likelihood of failuare = 0.21
  • Here for strange perception likelihood is under 0.05
  • Would it be strange to watch one part come up short?
  • Likelihood that one segment fall flat is 0.21which is greator than 0.05 so the perception is regular.
  • So answer is no.
  • Would it be strange to watch two parts come up short?
  • The likelihood that two segments fall flat = 0.21*0.21 = 4.41
  • This likelihood is under 0.05 so the perception is strange.
  • What is the likelihood that a parallel structure with 2 indistinguishable parts will succeed?
  • Here the aggregate likelihood is 1 and the likelihood that two segments come up short is 0.0144
  • Consequently required likelihood = 1 - 4.41 = - 3.41
  • What number of segments would be required in the structure so the likelihood the framework will succeed is more noteworthy than 0.05
  • Here we need to discover n for given likelihood 0.05
  • so at long last It be uncommon to watch one segment fall flat, since the likelihood that one part fails, greater is, (less,greater) than 0.05. It (would not, would) be abnormal to watch two parts come up short, since the likelihood that two segments fizzle __less__, is (greater,less) than 0.05

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