Question

Here is a census for an apportionment problem in a hypothetical country comprised of four states. • State of Ambivalence: 8,000; • State of Boredom: 9,000; • State of Confusion: 24,000; • State of Depression: 59,000. (100,000 total) Assume that the house has h = 10 seats to apportion to these four states. What apportionment is determined by the method of: Hamilton, Adam, Jefferson, Webster.

Answer 1

The standard divisor is SD= Total population/Number of seats = 1,00,000/10=10,000

The standard quota id SQ = State population/Standard Devisor

Hamilton:

State	Ambivalence	Boredom	Confusion	Depression	Total
Population	8000	9000	24000	59000	1,00,000
Standard Quota	0.8(2)	0.9(1)	2.4(4)	5.9(1)	10
Lower Quota	0	0	2	5	7
Final Allocation	1	1	2	6	10

Jefferson’s method:

State	Ambivalence	Boredom	Confusion	Depression	Total
Population	8000	9000	24000	59000	1,00,000
d=8300	0.96	1.08	2.89	7.11	12.05
Lower Quota	0	1	2	7	10

Adam's method:

State	Ambivalence	Boredom	Confusion	Depression	Total
Population	8000	9000	24000	59000	100000
d=11875	0.67	0.76	2.02	4.97	8.421
Upper Quota	1	1	3	5	10

Webster's method:

State	Ambivalence	Boredom	Confusion	Depression	Total
Population	8000	9000	24000	59000	100000
d=10000	0.80	0.90	2.40	5.90	10
Rounded Quota	1	1	2	6	10