In: Statistics and Probability
The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1200 voters in the town and found that 76% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 73%. Make the decision to reject or fail to reject the null hypothesis at the 0.10 level.
Solution :
Given that,
= 0.73
1 -
= 0.27
n = 1200
Level of significance =
= 0.10
Point estimate = sample proportion =
= 0.76
This a right (One) tailed test.
A)
Ho: p = 0.73
Ha: p
0.73
Test statistics
z = (
-
) /
*(1-
)
/ n
= ( 0.76 - 0.73) /
(0.73*0.27) /1200
= 2.34
P-value = P(Z>z)
= 1 - P(Z <z )
= 1- P(Z < 2.34)
= 1 - 0.9904
= 0.0096
The p-value is p = 0.0096, and since p = 0.0096 < 0.10, it is concluded that the null hypothesis is rejected.