In: Statistics and Probability
The mayor of a town has proposed a plan for the construction of a new community. A political study took a sample of 900 voters in the town and found that 75% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is more than 72%. Testing at the 0.05 level, is there enough evidence to support the strategist's claim?
Solution :
Given that,
= 0.72
1 - = 0.28
n = 900
Level of significance = = 0.05
Point estimate = sample proportion = = 0.75
This a right (One) tailed test.
The null and alternative hypothesis is,
Ho: p = 0.72
Ha: p 0.72
Test statistics
z = ( - ) / *(1-) / n
= ( 0.75 - 0.72) / (0.72*0.28) / 900
= 2.004
P-value = P(Z>z)
= 1 - P(Z <z )
= 1- P(Z < 2.004)
= 0.0225
The p-value is p = 0.0225, and since p = 0.0225 < 0.05, it is concluded that the null hypothesis is rejected.
Conclusion:
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the percentage of residents who favor construction is more than 72%. at the α = 0.05 significance level.