In: Statistics and Probability
he mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1000 voters in the town and found that 57% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 53%. Make the decision to reject or fail to reject the null hypothesis at the 0.20 level.
Ho : p = 0.53
H1 : p > 0.53
(Right tail test)
Level of Significance, α =
0.20
Number of Items of Interest, x =
570
Sample Size, n = 1000
Sample Proportion , p̂ = x/n =
0.5700
Standard Error , SE = √( p(1-p)/n ) =
0.0158
Z Test Statistic = ( p̂-p)/SE = ( 0.5700
- 0.53 ) / 0.0158
= 2.5344
p-Value = 0.0056 [Excel
function =NORMSDIST(-z)
Decision: p-value<α =0.20 , reject null
hypothesis
There is enough evidence to support the claim
that the percentage of residents who favor
construction is above 53%