Question

1. Write a function convert_date that takes an integer as a parameter and returns three integer values representing the input converted into days, month and year (see the function docstring).

Write a program named t03.py that tests the function by asking the user to enter a number and displaying the output day, month and year. Save the function in a PyDev library module named functions.py

A sample run for t03.py:

Enter a date in the format MMDDYYYY: 05272017

The output will be:

27/05/2017

The function docstring is as follows:

def convert_date (date_int): """

-------------------------------------------------------

Converts date_int into days, month and year use: day,month,year = convert_date (date_int)

-------------------------------------------------------

Paramaters:

date_int – (int > 0)

returns

day: the day in the month in date_int (int >= 0)

month: the month in date_int (int >=0) year: the years in date_int (int >=0)

------------------------------------------------------- """

• Test your program with 2 different date values than those given in the example.
• You may assume that the user will only enter numbers (2 digits for month, 2 digits for days and 4 digits for year)
• You are not allowed to use any string methods or string indexing.
• Copy the results to testing.txt.

Answer 1

Program Code Screenshot:

Sample output:

The screenshots are attached below for reference.

Please follow them for proper indentation and output.

Program to copy:

def convert_date (date_int):
temp=date_int
c=0
res=""
while temp!=0:#getthe number of digits
temp=temp//10
c+=1
  
if(c==7):#if number of digits is 7 then it means that 0 is present in first place
k=date_int//100000#perform arithmetic operations on the date_int and print the results
print((k%10),end="")
k=date_int//10000
print(k%10,end="")
print("/"+"0",end="")#print the / characters and add 0
print((date_int//1000000),end="")
print("/",end="")
k=date_int%10000
print(k)
else:
k=date_int//10000
print(k%100,end="")
print("/",end="")
k=date_int//1000000#perform arithmetic operations on the date_int and print the results
print((k),end="")
print("/",end="")
k=date_int%10000
print(k)

date=int(input("Enter a date in the format MMDDYYYY:"))#read input of integer type
convert_date(date)#call function

Note:

Please let me know in case of any help needed in the comments section.