Write a function called draw_card. It takes no arguments and returns an integer representing the value...

Write a function called draw_card. It takes no arguments and returns an integer representing the value of a blackjack card drawn from a deck. Get a random integer in the range 1 to 13, inclusive. If the integer is a 1, print "Ace is drawn" and return 1. If the integer is between 2 and 10, call it x, print "<x> is drawn" and return x (print the number, not the string literal "<x>"). If the number is 11, 12, or 13, print "Jack", "Queen", or "King", respectively, "is drawn" and return 20.

Solutions

Expert Solution

import random

#draw_card function
def draw_card():
    
    #selects an integer from 1 to 13 in num 
    num = random.randint(1,13)
    
    #for int is 1
    if num == 1:
        print("Ace is drawn")
        return 
    
    #for int is between 2 to 10
    elif num>= 2 or num <= 10:
        x = num
        print(str(x) + " is drawn")
        return x
        
    #for Jack
    elif num == 11:
        print("Jack is drawn")
        return 20
    
    #for Queen
    elif num == 12:
        print("Queen is drawn")
        return 20 
        
    #for King
    elif num == 13:
        print("King is drawn")
        return 20
            
#function call of draw_card
num = draw_card()

Please refer below screenshot of code for indentation purpose and output

Output also shown in the same.

venereology answered 1 year ago

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