In: Statistics and Probability
Fasting concentrations (mmol/L) of glucose in blood were measured in a sample of diabetic patients implanted with a new insulin delivery platform.
| 
 P#1  | 
 P#2  | 
 P#3  | 
 P#4  | 
 P#5  | 
 P#6  | 
 P#7  | 
 P#8  | 
 P#9  | 
 P#10  | 
| 
 5.5  | 
 4.8  | 
 3.8  | 
 4.0  | 
 5.2  | 
 5.1  | 
 4.8  | 
 4.4  | 
 4.2  | 
 6.1  | 
Computer simulations of the platform predicted a fasting glucose level of 4.5 mmol/L.
Use a statistical test to fundament your opinion on whether the data is consistent with the model prediction.
(a)
H0: Null Hypothesis: 
 = 4.5
HA: Alternative Hypothesis: 
 4.5
(b)
t - test is suitable for this problem, because:
(i) The dependent variable is continuous.
(ii) The observations are independent of one another
(iii) The dependent variable should be approximately normally distributed - Though this condition is not explicitly stated, the same can be assumed.
(iv) The dependent variable does not contain outliers.
(c)
= 0.01
ndf = n - 1 = 10 - 1 = 9
From Table, critical values of t = 
 3.2498
From the given data the following statistics are calculated:
n = 10
 = 4.79
s =0.7141
SE = s/
= 0.7141/
=
0.2258
Test statistic is:
t = (4.79 -4.5)/0.2258 = 1.28
Since the calculated value of t = 1.28 is less than critical value of t = 3.2498, the difference is not significant. Fail to reject null hypothesis.
Conclusion: The data is consistent with the computer model.
(d)
t score = 1.28
ndf = 9
Two Tail test
By Technology, p - value= 0.2326
Since p - value = 0.2326 is greater than 
 = 0.01, the
difference is not significant. Fail to reject null hypothesis.
Conclusion: The data is consistent with the computer model.