In: Statistics and Probability
Fasting concentrations (mmol/L) of glucose in blood were measured in a sample of diabetic patients implanted with a new insulin delivery platform.
P#1 |
P#2 |
P#3 |
P#4 |
P#5 |
P#6 |
P#7 |
P#8 |
P#9 |
P#10 |
5.5 |
4.8 |
3.8 |
4.0 |
5.2 |
5.1 |
4.8 |
4.4 |
4.2 |
6.1 |
Computer simulations of the platform predicted a fasting glucose level of 4.5 mmol/L.
Use a statistical test to fundament your opinion on whether the data is consistent with the model prediction.
(a)
H0: Null Hypothesis: = 4.5
HA: Alternative Hypothesis: 4.5
(b)
t - test is suitable for this problem, because:
(i) The dependent variable is continuous.
(ii) The observations are independent of one another
(iii) The dependent variable should be approximately normally distributed - Though this condition is not explicitly stated, the same can be assumed.
(iv) The dependent variable does not contain outliers.
(c)
= 0.01
ndf = n - 1 = 10 - 1 = 9
From Table, critical values of t = 3.2498
From the given data the following statistics are calculated:
n = 10
= 4.79
s =0.7141
SE = s/
= 0.7141/= 0.2258
Test statistic is:
t = (4.79 -4.5)/0.2258 = 1.28
Since the calculated value of t = 1.28 is less than critical value of t = 3.2498, the difference is not significant. Fail to reject null hypothesis.
Conclusion: The data is consistent with the computer model.
(d)
t score = 1.28
ndf = 9
Two Tail test
By Technology, p - value= 0.2326
Since p - value = 0.2326 is greater than = 0.01, the difference is not significant. Fail to reject null hypothesis.
Conclusion: The data is consistent with the computer model.