In: Statistics and Probability
It is claimed that the mean of a population is 67. A random sample was obtained and is represented by data labelled “problem 9”. Complete the hypothesis test with α=5%. Use p-value method.
49.5 |
69.3 |
80.5 |
81.9 |
70 |
62.2 |
76.7 |
92.4 |
92.7 |
70.9 |
95.5 |
62.5 |
69.1 |
70.9 |
79.6 |
68.4 |
88 |
52.3 |
95.5 |
85.8 |
61.2 |
98.1 |
100.1 |
68.8 |
76.3 |
66.9 |
103.2 |
79.8 |
60.1 |
37.3 |
55.3 |
83.6 |
83.7 |
76.9 |
71.6 |
67.6 |
69.9 |
80.9 |
102.2 |
85.1 |
Calculation | |||
x | x-mean | (x-mean)2 | |
49.5 | -26.5575 | 705.3008063 | |
69.3 | -6.7575 | 45.66380625 | |
80.5 | 4.4425 | 19.73580625 | |
81.9 | 5.8425 | 34.13480625 | |
70 | -6.0575 | 36.69330625 | |
62.2 | -13.8575 | 192.0303063 | |
76.7 | 0.6425 | 0.41280625 | |
92.4 | 16.3425 | 267.0773063 | |
92.7 | 16.6425 | 276.9728063 | |
70.9 | -5.1575 | 26.59980625 | |
95.5 | 19.4425 | 378.0108063 | |
62.5 | -13.5575 | 183.8058063 | |
69.1 | -6.9575 | 48.40680625 | |
70.9 | -5.1575 | 26.59980625 | |
79.6 | 3.5425 | 12.54930625 | |
68.4 | -7.6575 | 58.63730625 | |
88 | 11.9425 | 142.6233063 | |
52.3 | -23.7575 | 564.4188063 | |
95.5 | 19.4425 | 378.0108063 | |
85.8 | 9.7425 | 94.91630625 | |
61.2 | -14.8575 | 220.7453063 | |
98.1 | 22.0425 | 485.8718063 | |
100.1 | 24.0425 | 578.0418062 | |
68.8 | -7.2575 | 52.67130625 | |
76.3 | 0.2425 | 0.05880625 | |
66.9 | -9.1575 | 83.85980625 | |
103.2 | 27.1425 | 736.7153063 | |
79.8 | 3.7425 | 14.00630625 | |
60.1 | -15.9575 | 254.6418063 | |
37.3 | -38.7575 | 1502.143806 | |
55.3 | -20.7575 | 430.8738063 | |
83.6 | 7.5425 | 56.88930625 | |
83.7 | 7.6425 | 58.40780625 | |
76.9 | 0.8425 | 0.70980625 | |
71.6 | -4.4575 | 19.86930625 | |
67.6 | -8.4575 | 71.52930625 | |
69.9 | -6.1575 | 37.91480625 | |
80.9 | 4.8425 | 23.44980625 | |
102.2 | 26.1425 | 683.4303063 | |
85.1 | 9.0425 | 81.76680625 | |
sum= | 3042.3 | 8886.19775 | |
mean= | 76.0575 | 222.1549438 | |
variance= | 222.155 | ||
standard deviation= | sqrt(222.155) | ||
standard deviation= | 14.90486309 |
Given = 67 population mean , level =5%
We have n=40 , = 76.0575 , S= 14.9048
here sample size is large so we can use Z test
Null hypothesis H0: = 67
H1: 67 two tailed alternative
Test statistics
The P-Value is 0.00012
Decision : The P-Value (0.00012) < 0.05
so Reject Ho
Conclusion: We conclude that the claim that the mean of a population is 67 is not true