Question

Under electrostatic condition electric charge Q = 17.7x10-9 C is uniformly distributed on the surface of an isolated conducting sphere of radius R = 3 m. There is no other charge around. (a) What is the electric flux through a concentric spherical surface of radius 2R. (b) What is the electric potential at the surface of the conducting sphere? What is the electric field inside the conducting sphere? Please explain the steps and formuals .Mandatory !!

Answer 1

Let us consider an imaginary surface, usually referred to as a Gaussian surface, which is a sphere of radius 2 lying above the surface of the conducting sphere. Since the electric field-lines are everywhere normal to this surface, Gauss' law tells us that

where is the electric flux through the gaussian surface, A = 4 the area of this surface, and the electric field-strength just above the surface of the conductor. Note that, by symmetry, is uniform over the surface of the conductor.

Flux = 8.0 x 10 ³

The potential has a fixed value at all points within the conducting sphere equal to the potential at the surface.

Putting values

V = 52.98

Electric field at center of conducting sphere is zero.