Question

In: Other

100 lbmoles of Methane is feed into a partial oxidizer with 160 lbmoles of dry air...

100 lbmoles of Methane is feed into a partial oxidizer with 160 lbmoles of dry air which also contains water(humidity = 0.050 lb water/lb dry air). The methane partially oxidizes to produce CO according to: CH4 + 3/2 O2 —> CO + 2H2O If the outlet gas contains 45.00% (mole %, wet basis) nitrogen, what is the reaction conversion based on the limiting reactant?

Solutions

Expert Solution

to solve this problem, we will first draw the flow diagram and determine the unknowns.

then, with the help of reaction equation and amount of reactants provided, we will determine the limiting reactant and then we will calculate its conversion.

hence, the conversion of the limiting reactant, i.e., oxygen = 71.52 %

Amanda K answered 6 months ago
Next > < Previous

Related Solutions

100 lbmoles of Methane is feed into a partial oxidizer with 160 lbmoles of dry air...
100 lbmoles of Methane is feed into a partial oxidizer with 160 lbmoles of dry air which also contains water(humidity = 0.050 lb water/lb dry air). The methane partially oxidizes to produce CO according to: CH4 + 3/2 O2 —> CO + 2H2O If the outlet gas contains 45.00% (mole %, wet basis) nitrogen, what is the reaction conversion based on the limiting reactant?
Methanol (CH3OH) is produced via the partial oxidization of methane (CH4). The fresh feed contains methane...
Methanol (CH3OH) is produced via the partial oxidization of methane (CH4). The fresh feed contains methane and oxygen that have been mixed in stoichiometric proportions. This feed is mixed with recycle gases. The single-pass conversion of methane is 10.0%. The stream leaving the reactor is passed into a separation process where the entire methanol, and none of the other materials, is removed. All of the remaining materials are recycled to be mixed with the fresh feed. Determine the feed rate...
Methane is burned with air and the exhaust products are measured (on a dry, volumetric basis)...
Methane is burned with air and the exhaust products are measured (on a dry, volumetric basis) to be 4.8% CO2, 0.12% CO, 12.25% O2, and balance N2. Determine (a) the air-tofuel ratio (mass based) (5 points), (b) equivalence ratio (5 points) (c) the percent theoretical air (%) (5 points), (d) the percent excess air (%) (5 points), and (e) exhaust dew point (°C) if the exhaust is at 1 atm (5 points). (25 points)
Methane is burned with air and the exhaust products are measured (on a dry, volumetric basis)...
Methane is burned with air and the exhaust products are measured (on a dry, volumetric basis) to be 4.8% CO2, 0.12% CO, 12.25% O2, and balance N2. Determine (a) the air-tofuel ratio (mass based) (5 points), (b) equivalence ratio (5 points) (c) the percent theoretical air (%) (5 points), (d) the percent excess air (%) (5 points), and (e) exhaust dew point (°C) if the exhaust is at 1 atm (5 points). (25 points)
Calculate the partial pressure of O2 (P02, mm Hg) in dry air in Arcata (sea level-...
Calculate the partial pressure of O2 (P02, mm Hg) in dry air in Arcata (sea level- assume atmospheric pressure of 760 mm Hg). Arcata air never gets fully dry. Assume 90% humidity at 15°C (saturated water vapor pressure at 15°C=12.8 mm Hg) and calculated the actual partial pressure of O2 in Arcata air.
Methane is burning with minimum amount of air to form the stable products. The premixed methane-air...
Methane is burning with minimum amount of air to form the stable products. The premixed methane-air mixture is filled in a leak-proof spherical vessel at an initial pressure of 1 bar and 298 K. The vessel is well insulated to avoid thermal energy interaction with the surroundings.The combustible mixture is ignited at the centre of the vessel using an electrical spark. The energy added to the mixture for ignition is negligible. During the combustion process, the pressure of the combustion...
“Dry air” is defined as air with no water vapor, and the molecular weight of air,...
“Dry air” is defined as air with no water vapor, and the molecular weight of air, Mair = 28.97 kg/kmol, is for dry air (zero humidity). “Wet air” is typically defined as air with 100% humidity. (a) Calculate the mol fraction of water vapor in wet air at STP conditions. Give your answer in units of PPM to three significant digits. (b) Compare the molecular weight of dry air and wet air at STP conditions. Which air is heavier? Explain....
9.77 Methane is burned with 25% excess air in a continuous adiabatic reactor. The methane enters...
9.77 Methane is burned with 25% excess air in a continuous adiabatic reactor. The methane enters the reactor at 25 C and 1.10 atm at a rate of 550 L/s, and the entering air is at 150 C and 1.1 atm. Combustion in the reactor is complete, and the reactor effluent gas emerges at 1.05 atm. a) Calculate the temperature and the degrees of superheat of the reactor effluent. (Consider water to be the only condensable species in the effluent)....
Show that the density of moist air is less than that of dry air both at...
Show that the density of moist air is less than that of dry air both at the same temperature and pressure. Does this difference between the densities of moist air and dry air, for given pressure and temperautre have any relevance to atmospheric processes?
At steady state, 100 m^3/min of dry air at 32 C, 1 bar is mixed adiabatically...
At steady state, 100 m^3/min of dry air at 32 C, 1 bar is mixed adiabatically with a stream of oxygen at 127 C, 1 bar to form a mixed stream at 47 C, 1 bar. Kinetic and potential energy effects can be ignored. Find: (a) the mass flow rates of the dry air and the oxygen (b) the mole fractions of the dry air and oxygen in the exiting mixture (c) the time rate of entropy production
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT