In: Statistics and Probability
Irritable bowel syndrome (IBS) is a nonspecific intestinal disorder characterized by abdominal pain and irregular bowel habits. Each person in a random sample of 24 patients having periodic attacks of IBS was randomly assigned to one of three treatment groups, A, B, and C. The number of hours of relief while on therapy is recorded for each patient in the table below.
Treatment |
|||
A |
B |
C |
|
11.2 |
11.6 |
23.1 |
|
8.0 |
12.5 |
9.9 |
|
8.1 |
10.6 |
12.1 |
|
10.9 |
11.6 |
13.0 |
|
12.3 |
13.9 |
13.3 |
|
9.9 |
8.6 |
11.0 |
|
9.1 |
18.9 |
15.2 |
|
15.0 |
19.1 |
15.9 |
|
sample mean |
10.5625 |
13.35 |
14.1875 |
sample variance |
5.4913 |
14.4486 |
16.9270 |
question 1Give the value of the analysis of variance test statistic used to test H0: μA = μB = μC.
1 points
Question 2
What's the critical value if the .10 significance level is used?
1 points
Question 3
What's the p-value?
1 points
Question 4
What's the decision using the .05 significance level?
Reject H0 |
||
Don't Reject H0 |
||
Reject HA |
||
Don't Reject HA |
Q.1 ) Test statistics F = 2.34 (Rounded to two decimal places)
Q.2) We have given =0.10 Hence we get Critical value Fcritical = 2.57 (Rounded to two decimal places)
Q.3) From the ANOVA table we get P value = 0.1205 (Rounded to four decimal places)
Decision rule :
If p value then reject H0.
If p value > then fail to reject H0.
Here p value is greater than 0.05 Hence we fail to reject H0.
Hence Don't Reject H0
Hope this will help you. Thank you :)