Question

The SBD Dauntless was a dive-bomber that was used by the United States Navy during World War II. Consider one such aircraft flying with a velocity of 103 m/s at an angle θ below the horizontal. The aircraft releases a bomb when its altitude is 2.15 km above sea level. At the point when the bomb is released, the magnitude of the displacement from the bomb to its target at sea level is 2.68 km. What is the angle θ? (Give your answer in degrees. Consider θ to be a positive value, measured downward from the horizontal axis.)

_________ ° downward from the horizontal

Answer 1

Given launch velocity,

initial vertical velocity,

initial horizontal velocity,

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Find X

Consider horizontal motion of bomb

Horizontal speed =horizontal distance /time

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Consider vertical motion of bomb

Use formula

Solve quadratic equation using a calculator

ANSWER:

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