In: Finance
Maximus Steel plans to introduce one of three new products code-named: Wren, Hawk, and Nightingale. The marketing department indicated that the success of any product depends on the market conditions (Favorable, Neutral, or Unfavorable). The profit the company will earn also depends on the market conditions.
The table below shows the probability estimated for each market condition and the profits Maximus Steel will realize within those conditions:
Product Code |
Market Conditions |
||
Favorable P = 0.2 |
Neutral P = 0.7 |
Unfavorable P = 0.1 |
|
Wren |
$120,000 |
$70,000 |
($30,000) |
Hawk |
$60,000 |
$40,000 |
$20,000 |
Nightingale |
$35,000 |
$30,000 |
$30,000 |
Part 1 Instructions:
Part 2:
Maximus Steel is considering hiring a market research firm to do a survey to determine future market conditions. The results of the survey will indicate either positive or negative market conditions.
There is a 0.60 probability of a positive report, given favorable conditions; a 0.30 probability of a positive report, given neutral conditions; and a .10 probability of a positive report, given unfavorable conditions.
There is a .90 probability of a negative report, given unfavorable conditions; a .70 probability, given neutral conditions; and a .40 probability, given favorable conditions.
Develop a full decision tree for Maximus Stell. Determine the best strategy for the company, the expected value of the strategy, and the maximum amount the company should pay the market research firm for the survey results.
Note: This is all the info I have. Can you please just guide in the right direction for the decision tree. Thanks
ANS: 1. Expected value of each alternative is as follows:
(I) | Profit | Favourable | |
Waren | $ 120,000.00 | 0.2 | $ 24,000.00 |
Hawk | $ 60,000.00 | 0.2 | $ 12,000.00 |
Nightingale | $ 35,000.00 | 0.2 | $ 7,000.00 |
Value expected | $ 43,000.00 | ||
(II) | |||
Profit | Favourable | ||
Waren | $ 70,000.00 | 0.7 | $ 49,000.00 |
Hawk | $ 40,000.00 | 0.7 | $ 28,000.00 |
Nightingale | $ 30,000.00 | 0.7 | $ 21,000.00 |
Value expected | $ 98,000.00 | ||
(III) | |||
Profit | Favourable | ||
Waren | $ (30,000.00) | 0.1 | $ (3,000.00) |
Hawk | $ 20,000.00 | 0.1 | $ 2,000.00 |
Nightingale | $ 30,000.00 | 0.1 | $ 3,000.00 |
Value expected | $ 2,000.00 |
Best options among the above is (II) one which has highest expected value as a whole irrespective of each product profit.
Computation of Opportunity Loss | |||
Product | Profit in (II) | Profit in (I) | opportunity loss |
Waren | $ 70,000 | $ 120,000 | $ (50,000) |
Hawk | $ 40,000 | $ 60,000 | $ (20,000) |
Nightingale | $ 30,000 | $ 35,000 | $ (5,000) |
If company gives tender to a market research firm then it can not do this probability analysis and its opportunity cost which the company is currently bearing can be saved. So, maximum we can pay what is our saving if we execute the program, which is $75000.