Question

Calculate the mass of 1.00 mmol of trans-cinnamic acid and the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid.

Answer 1

cinnamic acid = C₉H₈O₂

2,3-dibromo-3-phenylpropanoic acid = C₉H₈O₂Br₂

Molar mass of cinnamic acid = 148.16 g/mole

Thus, mass of 0.001 moles of cinnamic acid = moles*molar mass = 0.14816 g

Now, 1 mole of cinnamic acid produces 1 mole of 2,3-dibromo-3-phenylpropanoic acid theoretically

Thus, 0.001 moles of cinnamic acid will produce 0.001 moles of 2,3-dibromo-3-phenylpropanoic acid

Thus, mass of 2,3-dibromo-3-phenylpropanoic acid produced theoretically = moles*molar mass = 0.001*307.97 = 0.308 g