When trans-cinnamic acid reacts with bromine, the product is
2,3-dibromo-3-phenylpropanoic acid.
You measure out 0.30 g...
When trans-cinnamic acid reacts with bromine, the product is
2,3-dibromo-3-phenylpropanoic acid.
You measure out 0.30 g of trans-cinnamic acid, 10 mL of
dichloromethane, and a 0.5M solution of bromine. When the reaction
is finished, you have 0.223 grams of 2,3-dibromo-3-phenylpropanoic
acid.
A. How many moles of trans-cinnamic acid was used?
Discuss the differences observed in the IR and NMR spectra of
(E)-cinnamic acid and 2,3-dibromo-3-phenylpropanoic acid that are
consistent with addition of bromine to the double bond.
In the bromination reaction of a chalcone, trans-4-nitrochalcone
reacts with Br2/CHCl3 to produce
erythro-2,3-diBromo-3-(4-nitrophenyl)propiophenone. The product is
a racemic mixture.
a) Draw the structure of the enantiomers you form and assign R
& S to each of the stereocenters.
b) Will you see two spots on a TLC plate for your reaction
products? Why or why not?
c) Draw the structures of the products that are not formed in
the bromination reaction.
d) Is this bromination reaction stereoselective? Why or...
Please describe in detail the mechanism for the formation of
2R,3S/2S,3R-2,3-dibromo-3-phenylpropanoic acid. Based on the
stereochemistry of bromine addition.
Please, don't only use drawings (although they can be of help),
i would pefer it written. Thankyou.
In Stereochemistry of bromine addition to trans-Cinnamic acid
lab we acquired a melting point of which matched erythro 2
3-dibromo-3-phenylpropanoic acid. Why was the product (or products)
formed by anti- addition? explain. what evidence in the lab would
help with explaining this? thank you!
List the signals you would expect to in an IR as evidence that
there is 2,3-dibromo-3- phenylpropanoic acid present as a
contaminant rather than pure 1-bromo-2-
phenylethene.