Please describe in detail the mechanism for the formation of
2R,3S/2S,3R-2,3-dibromo-3-phenylpropanoic acid. Based on the
stereochemistry of bromine addition.
Please, don't only use drawings (although they can be of help),
i would pefer it written. Thankyou.
Discuss the differences observed in the IR and NMR spectra of
(E)-cinnamic acid and 2,3-dibromo-3-phenylpropanoic acid that are
consistent with addition of bromine to the double bond.
When trans-cinnamic acid reacts with bromine, the product is
2,3-dibromo-3-phenylpropanoic acid.
You measure out 0.30 g of trans-cinnamic acid, 10 mL of
dichloromethane, and a 0.5M solution of bromine. When the reaction
is finished, you have 0.223 grams of 2,3-dibromo-3-phenylpropanoic
acid.
A. How many moles of trans-cinnamic acid was used?
B. What is the limiting reagent?
C. What is the theoretical yield (in moles)?
D. What is the actual yield (in moles)?
E. What is the total percent yield?
a.) Draw the structural formula of
(E)-1,2-dibromo-3-isopropyl-2-hexene
b.) Draw the structural formula of (Z)-3-methyl-2-heptene.
c.) Draw the structure for 1-chloro-3-hexyne
d.) Draw the structure for cyclooctyne
e.) Draw the structure for 4,4-dimethyl-1-pentyne