Question

In: Statistics and Probability

Part I - Do Students Really Cheat? (30%) In a recent poll 400 students were asked...

Part I - Do Students Really Cheat? (30%)

In a recent poll 400 students were asked about their experiences with witnessing academic dishonesty among their classmates. Suppose 172 students admitted to witnessing academic dishonesty, 205 stated they did not and 23 had no opinion. Use the sign test and a significance of 0.05 to determine whether there is a difference between the number of students that have witnessed academic dishonesty compared to those that have not.

Solutions

Expert Solution

The sign test is a statistical method to test for consistent difference between pairs of observation. Given pairs of observations ( such as weight pre and post treatment ) for each subject, the sign test determines if one member of the pair (such as pre-treatment ) tends to be greater than (or less than ) the other member of the pair (such as post treatment).

First of all, we set up the Hypothesis-

H​​​​​​0: There is no difference between number of students that have differenced academic dishonesty compared to those who have not.

H​​​​​​1: There is difference between number of students that have differenced academic dishonesty compared to those who have not.

The sign test is a non- parametric test which makes very few assumptions about the nature of the distributions under test- this means that it has very general applicability but may lack the Statistical power of the alternative tests.

Preferred A - Students admitted to witnessing dishonesty. (=172)

Preferred B - Students not admitted to witnessing dishonesty.

(=205)

No Preference - Number of ties.(=23)

p-value is 0.05 and z value is 24.286323

Which implies that p value is less than the z value, Hence null hypothesis is rejected and we may conclude that there is a difference between the number os students that have experienced academic dishonesty as compared to those who have not.


Related Solutions

In a recent poll on world sadness, participants were asked to rate how sad they were...
In a recent poll on world sadness, participants were asked to rate how sad they were on a scale of 0 to 10, with 0 being completely unhappy and 10 being incredibly unhappy. The standard deviation of responses was 1.9 and the mean response was 6.3. What response would be the 90th percentile, rounded to one decimal place? What response would be in the third quartile, rounded to one decimal place? Please show your work! Any help is appreciated!
In a recent poll, 120 people were asked if they liked dogs, and 60% said they...
In a recent poll, 120 people were asked if they liked dogs, and 60% said they did. Find the margin of error of this poll, at the 90% confidence level. Give your answer to three decimals
In a recent poll, 250 people were asked if they liked dogs, and 47% said they...
In a recent poll, 250 people were asked if they liked dogs, and 47% said they did. Find the margin of error of this poll, at the 90% confidence level. Give your answer to three decimals
In a recent poll, 160 people were asked if they liked dogs, and 55% said they...
In a recent poll, 160 people were asked if they liked dogs, and 55% said they did. Find the margin of error of this poll, at the 99% confidence level. Give your answer to three decimals If n=28, ¯xx¯(x-bar)=33, and s=7, find the margin of error at a 80% confidence level Give your answer to two decimal places.
1.) In a recent poll, 100 people were asked if they liked cats, and 81% said...
1.) In a recent poll, 100 people were asked if they liked cats, and 81% said they did. Based on this, construct a 99% confidence interval for the true population proportion of people who like cats. Use the following approximate critical values (z-scores) to perform the calculations by hand: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval. Give your answers as...
1. From a recent poll in which respondents were asked if they felt that U.S. nuclear...
1. From a recent poll in which respondents were asked if they felt that U.S. nuclear weapons made them feel safer, 550 out of 1000 people said “no.” a) Find the sample proportion, ?̂, of people who responded “no”. Use the appropriate formula and show your work. b) Find the margin of error for a 95% confidence interval for the true population proportion of people who feel that U.S. nuclear weapons do not make them feel safer. Round to three...
In a recent Gallup poll, 1003 randomly selected adults in the United States were asked if...
In a recent Gallup poll, 1003 randomly selected adults in the United States were asked if they have a gun in their home, and 37.2% of them answered “yes”. Construct a 95% confidence interval estimate of the percentage of all adults who would answer “yes” when asked if they have a gun in their home. [Write your answer as a complete sentence]
A group of 400 students that lived in on-campus housing were surveyed and asked if (1)...
A group of 400 students that lived in on-campus housing were surveyed and asked if (1) they had access to a car and (2) whether they owned a television. Suppose that a person collecting the data likes puzzles and she has given you the following information about the results of the poll. One hundred thirty of the students responded that they had access to a car, 240 students did not own a television, and 150 students both did not have...
In a recent national poll, people were asked the following question: "In your opinion, how important...
In a recent national poll, people were asked the following question: "In your opinion, how important is it to improve the nation's inner-city schools?" The responses of city residents who do not have school-age children were compared to the national responses. A chi square test was used to analyze the data in order to determine whether there is a difference in responses between those who live in cities and do not have school-age children and the national responses. The results...
In a recent Pew Research Center poll, 1503 adults were randomly selected and asked this question:...
In a recent Pew Research Center poll, 1503 adults were randomly selected and asked this question: "On average, how many hours of sleep do you get in a 24-hour period?" 55% answered 7 to 9 hours. 1) Explain what you could do statistically with this data. For example, could you build a confidence interval, perform a hypothesis test, use the normal distribution to find a probability, organize the information into graphs using descriptive statistics, etc. Explain at least two things...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT