Question

In: Statistics and Probability

1. From a recent poll in which respondents were asked if they felt that U.S. nuclear...

1. From a recent poll in which respondents were asked if they felt that U.S. nuclear weapons made them feel safer, 550 out of 1000 people said “no.”

a) Find the sample proportion, ?̂, of people who responded “no”. Use the appropriate formula and show your work.

b) Find the margin of error for a 95% confidence interval for the true population proportion of people who feel that U.S. nuclear weapons do not make them feel safer. Round to three decimal places. Use the appropriate formula and show your work.

c) Construct this 95% confidence interval. Round to three decimal places. Use the appropriate formula and show your work.

d) Write a statement interpreting the confidence interval you found in part (c).

Solutions

Expert Solution

Solution :

Given that,

n = 1000

x = 550

a) Point estimate = sample proportion = = x / n = 550 / 1000 = 0.55

1 - = 1 - 0.55 = 0.45

b) At 95% confidence level

= 1 - 95%

=1 - 0.95 =0.05

/2 = 0.025

Z/2 = Z0.025 = 1.960

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 (((0.55 * 0.45) / 1000)

= 0.031

c) A 95% confidence interval for population proportion p is ,

± E  

= 0.55  ± 0.031

= ( 0.519, 0.581 )

d) We are 95% confident that the true proportion  of people who feel that U.S. nuclear weapons do not make them feel safer between 0.519 and 0.581.


Related Solutions

A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=1000and x=557 who said "yes". Use a 90%confidence level. A) Find the best point estimate of the population P. (Round to three decimal places as needed) B) Identify the value of margin of error E. ________ (Round to four decimal places as needed) C) Construct a confidence interval. ___ < p <. (Round to three decimal places as needed) D) Write a statement that...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll of 968 randomly selected American adults, 511 of them responded with “yes.” a). Find the 95% confidence interval for the proportion of adults who felt vulnerable to identify theft . b). Write a statement that correctly interprets the confidence interval. Choose the correct answer below. A. One has 95% confidence that the sample proportion is equal to the population proportion. B. One has 95%...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1046 and x = 584 who said "yes." Use a 99% confidence level.
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll, n=941 and x=542 who said​ "yes." Use a 90% confidence level. 1. Find the best point estimate of the population proportion p. (round to three decimal places as needed) 2. Identify the value of the margin of error E (round to three decimal places as needed) 3. Construct the confident interval __< p < __ 4. write a statement that correctly interprets the confidence...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll, n equals 906 and x equals 529 who said​ "yes." Use a 90 % confidence level.
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=1023 and x=546 who said "yes". Use a 99% confidence level. A) Find the best point estimate of the population P. (Round to three decimal places as needed) B) Identify the value of margin of error E. ________ (Round to four decimal places as needed) C) Construct a confidence interval. ___ < p <. (Round to three decimal places as needed) D) Write a...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,...
A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll, n = 990 and x = 538 who said​ "yes." Use a 95 % confidence level.
1. A research institute poll asked respondents if they felt vulnerable to identity theft. In the...
1. A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll of 968 randomly selected American adults, 511 of them responded with “yes.” a). Find the 95% confidence interval for the proportion of adults who felt vulnerable to identify theft . b). Write a statement that correctly interprets the confidence interval. Choose the correct answer below. A. One has 95% confidence that the sample proportion is equal to the population proportion. B. One has...
1. In a recent campus survey, 75 Indiana students were asked if they felt that their...
1. In a recent campus survey, 75 Indiana students were asked if they felt that their education at Cleary was preparing them for their future careers and 83% of students responded “Extremely well prepared.” Construct a 95% confidence interval (use z= 1.96) for the true proportion of Cleary students who feel the same way. Round standard error to 4 decimal places. 2.   Is there anything you could do to get a narrower range of values in the previous problem? 3....
Large Sample Proportion Problem.  Surveys were conducted in multiple countries and respondents were asked if they felt...
Large Sample Proportion Problem.  Surveys were conducted in multiple countries and respondents were asked if they felt political news was reported fairly. The data for the United States is that out of 1,000 sampled, 470 indicated yes, they felt political news was reported fairly. Suppose we want to determine if the proportion for the U.S. is below .50. What is the standard error for this hypothesis test? Group of answer choices Cannot be determined from the information given. SQRT((.5*.5)/1000) SQRT((.47*.53)/1000 .4991/SQRT(1,000)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT