In a recent poll, 120 people were asked if they liked dogs, and 60% said they...

In a recent poll, 120 people were asked if they liked dogs, and 60% said they did. Find the margin of error of this poll, at the 90% confidence level.

Give your answer to three decimals

Solutions

Expert Solution

Solution :

Given that,

Point estimate = sample proportion = =0.60

1 - = 1- 0.60 =0.40

At 90% confidence level

= 1 - 90%

= 1 - 0.90 =0.10

/2 = 0.05

Z/2 = Z0.05 = 1.645 ( Using z table )

Margin of error = E Z/2 * $\sqrt$ (( * (1 - )) / n)

= 1.645 * $\sqrt$ ((0.60*0.40) /120 )

=0.074

orchestra answered 1 year ago

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