In: Statistics and Probability
In a recent poll, 120 people were asked if they liked dogs, and
60% said they did. Find the margin of error of this poll, at the
90% confidence level.
Give your answer to three decimals
Solution :
Given that,
Point estimate = sample proportion =
=0.60
1 -
= 1- 0.60 =0.40
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645 ( Using z table )
Margin of error = E Z/2
*
((
* (1 -
)) / n)
= 1.645 *((0.60*0.40)
/120 )
=0.074