In: Other
Refrigerant Entering mass flow rate mr = 6 kg/min
entering temperature T1 = 70 C and exit temperature T2 = 35 C at 1 MPa.
Water entering temperature tw1= 15 C and exit temperature tw2 = 25 C at constant pressure P = 300kPa
For refrigeration R-134a table :
At inlet condition (70C and 1 MPa) : specific enthalpy h1 = 452kJ/kg
Specific entropy s1 = 1.8265 kJ/kg.k
Exit condition (35 C and 1 MPa) : specific enthalpy h2 =249.05 kJ/kg
Specific entropy s2 = 1.1665 kJ/kg.k
For water table :
At inlet condition (15 C and 300kPa) : specific enthalpy hw1 = 63.269 kJ/kg
Specific entropy sw1 = 0.2244 kJ/kg.k
At final condition (25C and 300kPa) : specific enthalpy hw2 = 105.11 kJ/kg
specific entropy sw2 = 0.3671 kj/kg.k
a) applying energy balance for condenser: at steady state,
heat transfer by refrigerant = heat transfer by water
mr*(h1 - h2) = mw*(hw2 - hw1)
6 kg/min * (452 - 249.05)kJ/kg = mw*(105.11 - 63.269) kJ/kg
mw = 29 kg/min
mass flow rate of cooling water mw = 29 kg/min
b) heat transfer rate from refrigerant to the water,
Q = mr*(h1 - h2) = 6 kg/min * (452 - 249.5) = 1217.7 kJ/min * (1min/60s) = 20.295 kJ/s = 20.295 kW
Q = 20.295 kW
heat transfer from refrigerant to water Q = 20.295 kW
c) rate of entropy production within heat exchanger :
mass flow rate mw = 6 kg/min = 0.1 kg/s
Entropy change due to refrigerant R-134a, (ΔS)r= mw*(s2 - s1)
(ΔS)r = 0.1kg/s * (1.1665 - 1.8265)kj/kg.k = -0.066 kW/K
Entropy change due to water ΔSw = mw*(sw2 - sw1) = (29kg/min)*(1min/60s) * ( 0.3671 - 0.2244)kJ/kg.K = 0.0689 kW/K
Rate of entropy production within heat exchanger,
ΔSgen = ΔSr + ΔSw = - 0.066 + 0.0689 = 0.0029 kW/K
entropy generation ΔSgen = 0.0029 kW/K