In: Operations Management
Compute the capacity (bottleneck rate) in jobs per hour (jph) of the following configurations and record your numerical answers (in order) to the nearest tenth of jph. (Enter numbers only):
a. A station with two (2) machines operating in parallel with 5-minute process times (te) at each machine.
b. A balanced line with two (2) series single-machine stations, both with average processing times (te) of 10 minutes.
c. A line with four (4) single machine stations in series, where the average processing times are:
15, 18, 10, & 12 minutes respectively.
d. A four (4) station line with multi-machine stations A, B, C, & D, where the number of parallel machines are 2, 6 10, & 4 respectively. The average processing times (te) at each station are 10, 24, 40, & 18 minutes respectively (see table below).
Process Line with series stations & parallel machines per station Question (d)
Station |
te(minutes) |
te(hours) |
Machine jph(1/te) |
Machines/ station |
Station jph |
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A |
10 |
2 |
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B |
24 |
6 |
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C |
40 |
10 |
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D |
18 |
4 |
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Minimum rate (rb) = |
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a. A station with two (2) machines operating in parallel with 5-minute process times (te) at each machine. |
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no of machines |
2 |
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cycle time/machine |
5 |
min |
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capacity per machine |
12 |
parts/hour |
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since we have 2 machines processing 12 parts/hour. |
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total station capacity = 2*12 |
24 |
parts/hour |
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b. A balanced line with two (2) series single-machine stations, both with average processing times (te) of 10 minutes. |
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te |
10 |
min/part |
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capacity of one machine |
6 |
parts/hour |
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since, the machines are in series, |
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total station capacity |
6 |
parts/hour |
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c. A line with four (4) single machine stations in series, where the average processing times are: |
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15, 18, 10, & 12 minutes respectively. |
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station |
te (min) |
capacity (parts/hour) |
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1 |
15 |
4.0 |
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2 |
18 |
3.3 |
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3 |
10 |
6.0 |
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4 |
12 |
5.0 |
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Line capacity (bottleneck capacity) |
3.3 |
parts/hour |
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d. A four (4) station line with multi-machine stations A, B, C, & D, where the number of parallel machines are 2, 6 10, & 4 respectively. The average processing times (te) at each station are 10, 24, 40, & 18 minutes respectively (see table below). |
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Process Line with series stations & parallel machines per station Question (d) |
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Station |
te(minutes) |
te(hours) |
Machine jph(1/te) |
Machines/ station |
Station jph |
A |
10 |
0.17 |
6.0 |
2 |
12 |
B |
24 |
0.40 |
2.5 |
6 |
15 |
C |
40 |
0.67 |
1.5 |
10 |
15 |
D |
18 |
0.30 |
3.3 |
4 |
13.33333 |
Minimum rate (rb) = |
12 |
formulae used: