In: Economics
a) In () = 0.221Temp - 0.006Temp2+...
(Hence is never equal to zero)
To maximize Profit, we need d/d(Temp) = 0
Differentiating the equation wrt Temp on both sides and ignoring terms with powers 3 and greater(because their coefficients are low), we get:
(1/)*(d)/d(Temp)) = 0.221 - 0.006*2*Temp
d/d(Temp) = *(0.221 - 0.012Temp) = 0
Hence, either =0, or 0.221 - 0.012Temp = 0
But is never equal to zero and hence 0.221 - 0.012Temp = 0
Hence Temp = 0.221/0.012 = 18.417 C
Hence 18.417C maximizes profit.
b) = 0.221 - 0.006Temp2+.....
For profit maximization, d/d(Temp) = 0
Hence differentiating the equation wrt Temp, we get,
d/d(Temp) = 0.221 - 0.012Temp=0
Hence Temp = 18.417 C
Hence 18.417C maximizes profit in this case too.
c) In () = 0.221 Temp - 0.006 Temp2+.....
Hence = e0.221 Temp - 0.006 Temp2+....
If Temp = 24 C, then
= e0.221*24 - 0.006*24*24+....
= e1.848
= 6.347
If
Temp = 24 C, then
= e0.221*26 - 0.006*26*26+....
= e1.69
= 5.419
Hence the percentage decrease in profits = ((24 - 26)/24))*100
Hence the percentage decrease in profits = ((6.347 - 5.419)/6.347))*100
Hence the percentage decrease in profits = 14.621%
Hence profits decrease by 14.621%