Question

In: Physics

A beaker, filled to the very topwith water, weighs 15 N. A 300 g weight is...

A beaker, filled to the very topwith water, weighs 15 N. A 300 g weight is carefully dropped intothe beaker. The water that overflows is wiped away and the beakerreweighed. It weighs 16.9 N. What is the densityof the weight? [Use g=9.8m/s2.] Hint: The netforce on the bottom of the beaker after the weight is lowered tothe bottom is (the weight of the reduced volume of water) + (300 gweight).

Thebeaker is refilled to the top with water and a 100 g piece of woodof density 0.8 that of water is carefully floated on the water.What volume of water overflows?


NOTE: The claim is that melting of Arctic sea-ice, including largeicebergs, does NOT increase sea-level, but that melting ofGreenland or Antarctic glaciers does increasesea-level.

Why areboth claims made in the NOTE correct?

Solutions

Expert Solution

The initially filled beaker weighs 15N. The 300g weight by itself would weigh 0.3 X 9.8=2.94 N hence the combined weight of 15+2.94=17.94N

However the beaker now shows a weight of 16.9N which would mean that 1.04 N or equivalently 106 grams of water would have been displaced. Now we know that 1000 grams of water occupy 1000cc hence 106 grams would occupy 106cc of volume which was the volume of weight dropped in.

Since the mass is 300g, hence the density=mass/volume = 300/106=2.83g/cc

The 100g piece of wood that floats on water would displace an amount of water equal to its weight. Hence 100cc of water would be displaced.

The reason that Artic and Antartica regions do not contribute to rise in water levels is due to the Anomalous Expansion of Water. At temperatures below 4degrees celsius the density of ice is less than that of water and hence floats on top and thus the water levels do not rise.

In the Greenland regions however, the temprature of the ice is greater than 4 degrees with a higher density than water which causes it to sink and thus displace a quantity of water equal to its volume


Related Solutions

Submerged Sphere in a Beaker A cylindrical beaker of height 0.100m and negligible weight is filled...
Submerged Sphere in a Beaker A cylindrical beaker of height 0.100m and negligible weight is filled to the brim with a fluid of density ? = 890kg/m3 . When the beaker is placed on a scale, its weight is measured to be 1.00N .(Figure 1) A ball of density ?b = 5000kg/m3 and volume V = 60.0cm3 is then submerged in the fluid, so that some of the fluid spills over the side of the beaker. The ball is held...
A cylindrical beaker of height 0.100 m and negligible weight is filled to the brim with a fluid of density ρ = 890 kg/m3 . When the beaker is placed on a scale, its weight is measured to be 1.00 N
A cylindrical beaker of height 0.100 m and negligible weight is filled to the brim with a fluid of density ρ = 890 kg/m3 . When the beaker is placed on a scale, its weight is measured to be 1.00 N .(Figure 1) A ball of density ρb = 5000 kg/m3 and volume V = 60.0 cm3 is then submerged in the fluid so that some of the fluid spills over the side of the beaker. The ball is held...
A cubical box is filled with sand and weighs 578 N. We wish to "roll" the...
A cubical box is filled with sand and weighs 578 N. We wish to "roll" the box by pushing horizontally on one of the upper edges. (a) What minimum force is required? (b) What minimum coefficient of static friction between box and floor is required? (c) If there is a more efficient way to roll the box, find the smallest possible force that would have to be applied directly to the box to roll it. (Hint: At the onset of...
Let f(t) be the weight (in grams) of a solid sitting in a beaker of water...
Let f(t) be the weight (in grams) of a solid sitting in a beaker of water after t minutes have elapsed. Suppose that the solid dissolves in such a way that the rate of change (in grams/minute) of the weight of the solid at any time t can be determined from the weight using the forumula: f′(t)=−4f(t)(6+f(t)) If there is 1 grams of solid at time t=2 estimate the amount of solid 1 second later.
A 200 g insulated aluminum cup at 16 ∘C is filled with 255 g of water...
A 200 g insulated aluminum cup at 16 ∘C is filled with 255 g of water at 100 ∘C a) Determine the final temperature of the mixture. b)  Determine the total change in entropy as a result of the mixing process (use ΔS=∫dQ/T).
An object has a weight of 7.2 N in air. However, it apparently weighs only 3.9...
An object has a weight of 7.2 N in air. However, it apparently weighs only 3.9 N when it is completely submerged in water. What is the density of the object? a. 650 kg/m3 b. 3.3 x 103 kg/m3 c. 2.2 x 103 kg/m3 d. 7.2 x 103 kg/m3
The patient has stopped vomiting but is very dehydrated. He weighs 15 lbs and is diagnosed...
The patient has stopped vomiting but is very dehydrated. He weighs 15 lbs and is diagnosed at 8% dehydration. What is the total volume of fluids needed to correct his dehydration status in 24 hours? Use a maintenance rate of 3 ml/kg/hr. b. What is his hourly rate (ml/hr)? What is his drip rate using a 60 gtt/ml drip set (gtt/s)? What is his rate per hour for the first 12 hours if the Dr. wishes to correct his dehydration...
A single plant cell is placed in an open beaker containing deionised water. Very slowly, solutes...
A single plant cell is placed in an open beaker containing deionised water. Very slowly, solutes are added to the water, which is gently stirred. The cell is observed through a microscope. Eventually, the plasma membrane begins to pull away from the cell wall. a) Briefly explain why this occurred. [2 marks] The moment before the plasma membrane began to pull away from the cell wall, the osmotic potential in the bathing solution was –2.00 MPa. The bathing solution was...
sodium bicarbonate 10 g sodium carbonate 12.72 g, add-50 ml of deionized water to the beaker...
sodium bicarbonate 10 g sodium carbonate 12.72 g, add-50 ml of deionized water to the beaker and stir until all of the weak acid or weak base has dissolved. Carefully and slowly pour the weak acid or weak base solution into the volumetric flask. preparation of Buffer pour your weak acid and your weak base together into a bottle. How many grams of sodium bicarbonate (M.W.= 84.01 g/mole) would you have had to weigh out to make up 500ml of...
Archimedes measured the weight of the crown in air to be 11.8 N and its weight in water to be 10.9 N. Was it pure gold?
It is said that Archimedes discovered the buoyancy laws when asked by King Hiero of Syracuse to determine whether his new crown was pure gold (SG = 19.3). Archimedes measured the weight of the crown in air to be 11.8 N and its weight in water to be 10.9 N. Was it pure gold?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT