Question

----------USING JAVA-----------

Your objective is to beat the dealer's hand without going over 21.

• Cards dealt (randomly) are between 1 and 11.
• You receive 2 cards, are shown the total, and then are asked (in a loop) whether you want another card.
• You can request as many cards as you like, one at a time, but don't go over 21. (If you go over 21 it should not allow you any more cards and you lose)
• Determine the dealer's hand by generating a random number between 1 and 11 and adding 10 to it.
• Compare your hand with the dealer's hand and indicate who wins (dealer wins a draw)

Thank you!

Answer 1

Code is :

import java.util.*;

import java.lang.*;

import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */

class Demo

{

public static void main (String[] args) throws java.lang.Exception

{

  

int card1,card2,card3=0,dcard,tcard;

  

  

System.out.println("Hello.. Welcome to 21");

//Random number object

Random rand = new Random();

Scanner sc= new Scanner(System.in);

  

//selecting card 1

//1 is added to the random number to make it between 1-10

card1 = rand.nextInt(10);

card1 += 1;

  

//selecting card 2

card2 = rand.nextInt(10);

card2 += 1;

  

System.out.println(" Your first card is "+card1);

  

System.out.println(" Your second card is "+card2);

//adding user cards

tcard=card1+card2;

while (tcard<21)

{

//prompting user for another card

System.out.println(" Would you like another card... y/n");

  

String cr = sc.nextLine();

  

if (cr.equals("y"))  

{

//generating next card

card3 = rand.nextInt(10);

card3 += 1;  

System.out.println(" Your next card is "+card3);

tcard += card3;

}

else

{

break;

}

}

//generating dealer hand

dcard = rand.nextInt(10);

dcard += 1;

dcard += 10;

  

System.out.println("Dealer hand: "+dcard+" Your hand: "+tcard);

  

//checking winner

if ((tcard>21)||(tcard==dcard)||(tcard<dcard))  

System.out.println("Dealer wins");

else

System.out.println("You win");  

}

}

Input: y y n

Output: