In: Statistics and Probability
You are dealt a hand of five cards from a standard deck of 52 playing cards. Calculate the probability of the given type of hand. (None of them is a recognized poker hand.)
1. Double royal interracial wedding: Two kings of one color, two queens of the other color, and a last non-royal card (neither king, queen, jack or ace).
Solve using a formula.
Examples: C(5,3)C(33,3)/C(14,2) or C(5,3)C(33,3)C(4,1)/C(100,100)
Answer:-
Given That:-
You are dealt a hand of five cards from a standard deck of 52 playing cards. Calculate the probability of the given type of hand. (None of them is a recognized poker hand.)
1. Double royal interracial wedding: Two kings of one color, two queens of the other color, and a last non-royal card (neither king, queen, jack or ace).
Solve using a formula.
Examples: C(5,3)C(33,3)/C(14,2) or C(5,3)C(33,3)C(4,1)/C(100,100)
Given,
Total number of cards = 52
any 5 cards can be chosen in ways =
= 2598960
One colour can be chosen in
Number of kings are quuens in selected color (2 + 2) = 4
The number of ways 2 kings or 2 queens of one color can be chosen in ways
Number of non-royal cards of the remaining colour = (9 + 9) = 18
2 non royal cards at the remainaing colours can be chosen in
= 18!/(2! * 16!)
= 153
Remaining non royal denomination = (9 - 2)
= 7
5Th cards can be chosen = ways
= 7
Required probability =
= 0.0016
Thank you for your supporting. Please upvote my answer...