In: Chemistry
Part A: Using your graduated cylinder, you calibrate the pipet you will be using and the values you collect are as follow. What is the average number of drops per mL of benzene.
21 dropsdrops
23 dropsdrops
17 dropsdrops
Part B: After calibration, you use the oleic acid/benzene solution to form a monolayer. It takes 6 dropsdrops , 9 dropsdrops and 7 dropsdrops before the layer on the water solution starts to make a bubble tha does not go into solution. What is the average number of drops for your monolayer?
Part C: Since we have the number of drops it takes to make a monolayer and we have the number of drops it takes to make one mL of benzene, we can determine the mL of oleic acid/benzene it takes to form a monolayer.
Part D: Next we need to determine the mass of oleic acid in the monolayer. The concentration of the oleic acid/benzene solution is 0.02g/L. Calculate how many grams of oleic acid is in one drop.
Part E: With this information, we now need to calculate the volume in milliliters. We need to know how many mLs a drop of oleic acid occupies using the density of 0.895 g/mL and the number of drops of oleic acid solution used. (answer in mL/Drop)
Part F: Determine the volume of the monolayer from the above information.(in mL)
Part G:Calculate the thinkness of the monolayer assuming that the volume of the monolayer is 7.23×10−6 mLmL and diameter of the watch glass is 5 cm.( answer in cm)
Part H: Determine the number of moles of oleic acid in the monolayer. Assume the nubmer of grams of oleic acid in the monolayer is 7.54×10−6 (answer in Mol)
Part I: Calculate the surface area of one molecue if we assume the molecule is shaped like a cylinder that the hight is 10x larger than the radius.( answer in cm^2)
Part J: Determine the area of the surface covered by the molecues assuming they have a circular surface which at most can cover 90.6%. ( answer in cm^2)
Part K: Calculate the number of molecules in the surface.
Part L: Calculate the number of molecues in 1 mole of calculated oleic acid.
Part M: Compare this number based on the Avogadro's number finding the % error. Discuss why the % error is well over 100% and how that would be possible.