4. An albino man marries a normally-pigmented woman who had an albino mother. Show the types...

4. An albino man marries a normally-pigmented woman who had an albino mother. Show the types of children that this couple may have and the proportions of each. (Albino is recessive; normal is dominant).

Expert Solution

In an albino person both the alleles are recessive i.e. a/a.

In a non albino person the alleles maybe homozygous or heterozygous. Heterozygous is A/a and homozygous is A/A.

So in this case the father is is albino (a/a) and the mother is non albino (A/a). Mother is is not albino but is heterozygous carrier of albino allele because her mother was albino so the daughter must have received a recessive allele from her mother and the dominant allele from her father.

Alleles of the mother - A / a

Alleles of the father - a / a

Here - A is dominant allele, a is the recessive allele.

Father and Mother	A	a
a	A / a	a / a
a	A / a	a / a

As you can see in the above table the combination of various allele of mother and father are given. This gives the probability of all types of young ons that can be produced.

From the table we conclude that out of the total number of:-

1.Two child would be carrier but do not express the albino condition - A /a

2. Two child would be expressing the albino condition - a / a

Thus out of the the total number of child the probability of a child that is non albino but carrier is 1/2.

The probability of a child suffering from albino condition is 1/2.

Thank you. Please do like the answer. Thank you dear students.

gladiator answered 6 months ago

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