Question

In: Statistics and Probability

A researcher believes she has designed a keyboard that is more efficient to use than a standard keyboard.

Old New
16 12
9 9
17 15
10 8
9 5
4 4
30 25
29 21

A researcher believes she has designed a keyboard that is more efficient to use than a standard keyboard. In order to help decide if this is the case, typing speeds were taken for 16 different people. Eight of them are assigned to use old key board, and the other eight people are assigned to use the new key board. The lengths of time, in minutes, for each of the people to type a pre-selected manuscript are listed below. Assume the two population distributions are normal. Use the data in the Table to determine if the original keyboard yields slower times. Use a significance level of α = 0.05. Assume the two group has the same unknown population variance

Solutions

Expert Solution

: Population Mean length of time to type a pre-selected manuscript with old(original) key board

: Population Mean length of time to type a pre-selected manuscript with new key board

Claim : Original key board yields lower times : Mean length of Time taken with old key board is more than new key board or - > 0

Null hypothesis : Ho : - = 0

Alternate Hypothesis : Ha : - > 0

Right Tailed test :

The population variances of the two groups assumed equal.

Sample mean

Sample Standard deviation s:

For Old Key Board

n1 : Sample size =8

Old:x1
16 0.5 0.25
9 -6.5 42.25
17 1.5 2.25
10 -5.5 30.25
9 -6.5 42.25
4 -11.5 132.25
30 14.5 210.25
29 13.5 182.25
Total 124 642
Sample Mean: 124/8 = 15.5

Sample Mean length time to type a  pre-selected manuscript : = 15.5

Sample standard deviation to type a  pre-selected manuscript : s1

For new Key board

New: x2
12 -0.375 0.140625
9 -3.375 11.39063
15 2.625 6.890625
8 -4.375 19.14063
5 -7.375 54.39063
4 -8.375 70.14063
25 12.625 159.3906
21 8.625 74.39063
99 395.875
Sample Mean 99/8 = 12.375

Sample Mean length time to type a  pre-selected manuscript : = 12.375

Sample standard deviation to type a  pre-selected manuscript : s2

Degrees of freedom : df = n1 +n2 -2 = 8+8-2 =14

=0.05

For right tailed test :

As P-Value i.e. is greater than Level of significance i.e (P-value:0.2399 > 0.05:Level of significance); Fail to Reject Null Hypothesis
There is not sufficient evidence to conclude that original keyboard yields slower times


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