In: Statistics and Probability
1.) A researcher claims that Americans use more consonants in their language than the vowels. To test this claim, researcher randomly selects 26 English words (please randomly generate these English words by yourself and explicitly state them in your homework as your sample). Based on this sample;
a) State your hypothesis H0 and H1 claiming that Americans use more consonants in their language.
b) State the decision rule, sample statistics, table value and test statistic in the same order as in the extra solved examples on hypothesis testing.
c) Test, at the 97% level, the null hypothesis that the process is operating correctly
Following are the 26 randomly selected words and the number of vowels and consonants in each word
Average number of vowels = 2.8846
Average number of consonants = 4.0385
a)
The null and alternative hypotheses are
Ho : μ1 = μ2
Ha : μ1 > μ2
where μ1, μ2 are the population mean number of
consonants and vowels in a word respectively
b)
The sample statistics are given below :
n | Mean (M) | Variance (SS) | Standard Deviation (SD) | |
Number of consonants | n1 = 26 | M1 = 4.0385 | SS1 = 1.6385 | s1 = 1.28 |
Number of vowels | n2 = 26 | M2 = 2.8846 | SS2 = 1.5462 | s2 = 1.2434 |
We use independent Samples T test since population standard
deviation is unknown, and sample size is small
Degrees of
Freedom
df1 = n1 - 1 , df2 = n2 - 1 , df = n1 + n2 - 2
df = 50
Critical value (Table Value) t-crit is found using Excel function T.INV
97 % Level of significance
implies α = 0.03
Hence
t-critical = -T.INV(0.03, 50) (Negative sign is used since this is a right tailed test)
t-critical = 1.9244
Decision Rule:
Since this is a right tailed test, the decision rule is
Reject Ho if test statistic t > 1.9244
Using the given formulae, we get
Pooled
Variance
Sp2 = 1.5923
Mean Squared Error
Sm1-m2
Sm1-m2 = 0.35
t-statistic
t-statistic = t = 3.2969
c)
Now,
3.2969 > 1.9244
that is, calculated test statistic > table value
Hence, as per the decision rule, we reject Ho
Conclusion
There exists enough statistical evidence at 97% level of
significance to show that Americans use more consonants in
their language.
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