Question

In: Chemistry

1. Balance the following oxidation-reduction reactions using the half-reaction method and tell the number of electrons...

1. Balance the following oxidation-reduction reactions using the half-reaction method and tell the number of electrons transferred in the balanced oxidation-reduction reaction

a) S^2-(aq) + NO₃^-(aq) ---> S₈(s) + NO₂(g) acidic solution

b) MnO₄^-(aq) + I^-(aq) ---> MnO₂(s) + IO₃^-(aq) basic solution

c) Sb(s) + H₂SO₄(aq) ---> Sb₂(SO₄)₃(s) + SO₂(g) acidic solution

d) H₂O₂(aq) + MnO₄^-(aq) ---> MnO₂(s) + O₂(g) basic solution

Expert Solution

a) S^2-(aq) + NO₃^-(aq) ---> S₈(s) + NO₂(g)

oxidation half reaction : S^2-(aq) ----------> S₈(s)

8S^2-(aq) ----------> S₈(s) + 16 e-

reduction half reaction : NO₃^-(aq) ----------> NO₂(g)

NO₃^-(aq) + 2H+(aq) + e- ----------> NO₂(g) + H2O(l)

16 x ( NO₃^-(aq) + 2H+(aq) + e- ----------> NO₂(g) + H2O(l) )

16NO₃^-(aq) + 32H+(aq) + 16e- ----------> 16NO₂(g) + 16H2O(l)

8S^2-(aq) ----------> S₈(s) + 16 e-

16NO₃^-(aq) + 32H+(aq) + 16e- ----------> 16NO₂(g) + 16H2O(l)

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8S^2-(aq) + 16NO₃^-(aq) + 32H+(aq) ------------> S₈(s) + 16NO₂(g) + 16H2O(l)

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b)

oxidation half reaction : I-(aq) ---------------> IO3-(aq)

reduction half reaction : MnO4-(aq) --------------> MnO2(s)

balanced equation : 2 MnO4-(aq) + I-(aq) + H2O(l) ------------> 2 MnO2(s) + IO3-(aq) + 2OH-(aq)

total no.of electrons transferred = 6

c)

oxidation half reaction : Sb(s) ---------------> Sb3+(aq)

reduction half reaction : SO₄^2- (aq) ------------> SO2(g)

balanced : 2Sb + 12H+ + 3SO4-2 --> 2Sb+3 + 3SO2 + 6H2O

total no. of electrons transferred = 6

queen_honey_blossom answered 7 months ago

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