Question
In: Chemistry
One mole of an ideal gas (CP = 5R/2) in a closed piston/cylinder is compressed from...
One mole of an ideal gas (CP = 5R/2) in a closed
piston/cylinder is compressed
from Ti = 298 K, Pi = 0.1 MPa to Pf = 0.25 MPa by the
following pathways. For each
pathway, calculate ΔU, ΔH, Q, and WEC: (a) isothermal; (b)
constant volume; (c)
adiabatic.
i need your help as soon as possible please!!!
please give me step by step so i can understand it
Thank you!
Solutions
Expert Solution
The answer is as follow-
1) Isothermal -> w= -q , dH=dU=0
2) const. Volume -> w=0, dU=q=ncvvdT, dH=ncppdT
3) Adiabatic -> q=0, dU=ncvdT
queen_honey_blossom answered 1 week agoRelated Solutions
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Type or paste que
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CP=7R2 in a closed
piston/cylinder arrangement is compressed from
Ti=200 K , Pi=0.5
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ADIABATIC path
ISOTHERMAL path
Calculate ΔU, ΔH, Q and WEC for both paths.
NOTE: Keep the answers in terms of ‘R’.
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