Question

In: Math

According to the sixth annual survey of employees of advertising agencies, carried out by the company...

According to the sixth annual survey of employees of advertising agencies, carried out by the company Altschuler, Melvoin & Glasser, these employees can wait another excellent year for their compensation (Adveertising Age, December 1, 1997). To investigate if there is any difference in the annual compensation of artistic directors, suppose you select a random sample of 10 of them from each of four regions: West, South, North and Northeast, and what you want to do the research with 10% of error range.

West South North Northeast
60.9 50.8 49.5 65.9
45.9 39.6 42.3 58.6
62.1 44.2 35.5 49.3
66.6 40.0 49.1 52.9
68.0 53.9 56.7 48.5
65.0 45.4 41.4 52.9
49.4 61.1 51.3 52.4
62.3 42.3 49.4 48.1
62.6 38.4 42.1 13.2
57.2 38.3

55.7

45.9

Solutions

Expert Solution

Sol:

We shall do ANOVA single factor to check whether difference exists

In excel install analysis toolpak and then go to

Data>Data analysis >ANIOVA single factor

you get

Anova: Single Factor
SUMMARY
Groups Count Sum Average Variance
West 10 600 60 52.09333
South 10 454 45.4 57.90667
North 10 473 47.3 45.94444
Northeast 10 487.7 48.77 190.1801
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 1294.227 3 431.4089 4.985592 0.005394 2.866266
Within Groups 3115.121 36 86.53114
Total 4409.348 39

Null hypothesis:

All the 4 group means are equal

Alternative hypothesi:

Atleast one of the group means are different.

alpha=0.10

From ANOVA table

ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 1294.227 3 431.4089 4.985592 0.005394 2.866266
Within Groups 3115.121 36 86.53114
Total 4409.348 39

we get

we get

F=4.99

p=0.0054

p<0.01

Reject null Hypothesis

Accept alternative hypothesis.

Conclusion:

There is sufficient statistical evidence at 10% level of significance to conclude that there is difference in the annual compensation of artistic directors.


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