Question

In: Statistics and Probability

Problem:      Construct and interpret a 90%, 95%, and 99% confidence interval for the mean heights...

Problem:      Construct and interpret a 90%, 95%, and 99% confidence interval for the mean heights of either adult females or the average height of adult males living in America. Do not mix genders in your sample as this will skew your results. Gather a random sample of size 30 of heights from your friends, family, church members, strangers, etc. by asking each individual in your sample his or her height. From your raw data convert individual heights to inches. Record your raw data and your conversions in the table on page 2 of this document. Construct and interpret the confidence interval based on the raw data from your random sample. In a word processed document, answer the reflections questions below. Use the equation editor to show your calculations for the percent difference indicated in 6) below.

Reflections: 1)            Summarize the characteristics of your sample – how many was in it, who was in it, from where did you get your sample, what would you estimate to be the average age of your sample, etc.?

2) What is x for your sample?

3) What is s for your sample?

3) State and interpret the 90% confidence interval for your sample.

4) State and interpret the 95% confidence interval for your sample.

5) State and interpret the 99% confidence interval for your sample.

6) Research from a credible source the average height in the population as a whole for the group you sampled. Make sure to credit your source. Calculate a percent difference between the average of your sample and the average in the population as a whole.   What was the percent difference of the average height in your sample and the population as a whole? Comment on your percent difference.

Table of Raw Data of womens heights

Sample Number

Height in Feet and Inches

Height Converted to Inches

1

5 feet

60

2

5 feet 3 inches

63

3

5 feet 5 inches

65

4

5 feet 5 inches

65

5

5 feet 9 inches

69

6

5 feet 11 inches

71

7

5 feet 1 inch

61

8

5 feet 2 inches

62

9

5 feet 3 inches

63

10

5 feet 6 inches

66

11

6 feet

72

12

5 feet 11 inches

71

13

5 feet 4 inches

64

14

5 feet 8 inches

68

15

5 feet 8 inches

68

16

5 feet 4 inches

64

17

5 feet 7 inches

67

18

5 feet 5 inches

65

19

5 feet 5 inches

65

20

5 feet 2 inches

62

21

5 feet 5 inches

65

22

5 feet 9 inches

69

23

5 feet 2 inches

62

24

5 feet 3 inches

63

25

5 feet 1 inches

61

26

5 feet 4 inches

64

27

5 feet 5 inches

65

28

5 feet 5 inches

65

29

5 feet 3 inches

63

30

5 feet 6 inches66

66

Solutions

Expert Solution

Solution1:

in excel  

install anlaysis tool pack then go to data>data analysis>descriptive statistics.

select the data range

you will get

Height Converted to Inches
Mean 65.13333
Standard Error 0.566768
Median 65
Mode 65
Standard Deviation 3.104317
Sample Variance 9.636782
Kurtosis -0.21166
Skewness 0.600386
Range 12
Minimum 60
Maximum 72
Sum 1954
Count 30

mean=65.13333

median=65

mode=65

mean=median =mode

shape :symmetrical

follows normal distribution.

No outliers found

Solution2:

x of the sample is sample mean=xbar=65.1333

Solution3:

s of the sample is standard deviation=s=

3.104317

Solution4:

alpha=1-0.90=0.1

90% confidence interval for your sample.

xbar-MOE,xbar+MOE

MOE=margin of error=tcrit *s/sqrt(n)

MOE can be found in excel as

syntax is CONFIDENCE.T(alpha.samplesd,samplesize)

=CONFIDENCE.T(0.1;3.104317;30)

=0.963011079

90% lower limit=65.1333-0.963011079=64.17029

90% upper limit=65.1333+0.963011079=66.09631

we are 90% confident that the true population mean height of womens height lies in between

64.17029 and 66.09631 inches


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