Question

In: Statistics and Probability

TEST CORRECTIONS 5. In a study on the benefits of eating organic produce, fruit flies were...

TEST CORRECTIONS 5. In a study on the benefits of eating organic produce, fruit flies were assigned at random to two groups. One group was fed organic potatoes and the other was fed conventional potatoes. At the end of 13 days, the porportion of flies that were still alive was calculated for each group. To address the question of whether more flies would survive eating organic potatoes than conventional potatoes, we use the hypothesis HO: Porganic = Pconventional vs HA: Porganic > Pconventional

Part A: (got this right)

Part B: Suppose our primary concern is to protect the pubic from potentially harmful pesticides, as found in conventional potatues, and that if no statistically significant difference is found from this test, a grocery chain will stop selling organic potatoes. Is it safer to use a large or small significance level here? Explain in detail.

Part C: The p-value for the data in this study is 0.017. What is the conclusion of the test? State the conclusion in detailed context, using non-technical language.

Part D: A very large sample of fruit flies was used for this study. In the end, 35.8% of the flies eating organic potatoes were still alive, compared to 35.4% of the flies eating conventional potatoes. Comment on the PRACTICAL SIGNIFICANCE of this result. Make a clear distinction between practical and statistical significance.

Solutions

Expert Solution

Part~A: Null Hypothesis H0: Porganic = Pconventional vs Alternative hypotrhesis HA: Porganic > Pconventional

where Porganic =true proportion of eating organic potatoes

Pconventional=true proportion of eating conventional potatoes

Part B: It is safer to use use a large significance level.

Small significance level implies rejection region is small and large significance level implies rejection region is large. So if we accept null hypothesis with small significance level there is a possibility to reject null hypothesis with large significance level. Hence it is safer to use a large significance level here.

Part C: The p-value for the data in this study is 0.017. So, 0.01<p-value<0.05. So we reject null hypothesis at 5% level whereas we accept null hypothesis at 1% level. Therefore we conclude that more flies would survive eating organic potatoes than conventional potatoes at 5% level and at 1% level we can't conclude that more flies would survive eating organic potatoes than conventional potatoes.

Part D:

The practically difference between the proportions of eating organic and conventional potatoes= 0.358-0.354=0.004. However suppose we use a sample of size 1000 for both groups then

Test and CI for Two Proportions

Sample X N Sample p
1 358 1000 0.358000
2 354 1000 0.354000


Difference = p (1) - p (2)
Estimate for difference: 0.004
95% lower bound for difference: -0.0312214
Test for difference = 0 (vs > 0): Z = 0.19 P-Value = 0.426

Fisher's exact test: P-Value = 0.444
Here we reject null hypothesis i.e. insignificant difference between the proportions of eating organic and conventional potatoes at 5% level significance (since p-value>0.05)


Related Solutions

MORE BENEFITS OF EATING ORGANIC Using data from a study, we find a significant difference in...
MORE BENEFITS OF EATING ORGANIC Using data from a study, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data from this study.1 In this case, we are testing H0:po=pcHa:po>pc where po and pc represent the proportion of fruit flies alive at the end of the given time frame of those...
MORE BENEFITS OF EATING ORGANIC Using data from a study, we find a significant difference in...
MORE BENEFITS OF EATING ORGANIC Using data from a study, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data from this study.1 In this case, we are testing H0:po=pcHa:po>pc where po and pc represent the proportion of fruit flies alive at the end of the given time frame of those...
You will be investigating the benefits of eating organic foods. Students are asked to compare the...
You will be investigating the benefits of eating organic foods. Students are asked to compare the cost of organically-grown produce (i.e., apples or carrots) to the same produce that has been grown with conventional methods. This is opinion about whether you believe there are health benefits to eating organic foods. Do you believe the benefits outweigh the extra cost why or why not? You are to support your opinion with evidence from your readings and/or other resources.
Dihybrid crosses of (virtual) fruit flies (Drosophila melanogaster) were carried out at the computer lab at...
Dihybrid crosses of (virtual) fruit flies (Drosophila melanogaster) were carried out at the computer lab at this course. The mutant alleles studied were “vestigial wing” (vg) and “ebony body” (eb). The mutant P‐generation flies were homozygous recessive at both studied loci. The wild type alleles were homozygous dominant at both loci. The loci for vestigial wing and ebony body are located at separate chromosomes. Show the Punnett crosses from the P‐generation to the F1‐generation of mutant and wild type flies,...
Healthy women aged 18 to 40 participated in a study of eating habits. Subjects were given...
Healthy women aged 18 to 40 participated in a study of eating habits. Subjects were given bags of potato chips and bottled water and invited to snack freely. Interviews showed that some women were trying to restrain their diet out of concern about their weight. How much effect did these good intentions have on their eating habits? Here are the data on grams of potato chips consumed (note that the study report gave the standard error of the mean rather...
Healthy subjects aged 18 to 40 participated in a study of eating habits. Subjects were given...
Healthy subjects aged 18 to 40 participated in a study of eating habits. Subjects were given bags of potato chips and bottled water and invited to snack freely. Was there a difference between men and women in the number of potato chips consumed? Here are the data on grams of potato chips consumed. Group n Mean Standard Deviation Males 9 38 15 Females 11 12 10 We are interested in calculating a 90% confidence interval for the difference in mean...
5) Polychlorinated biphenyls (PCBs) are organic chlorine compounds that were widely used as dielectrics and coolants...
5) Polychlorinated biphenyls (PCBs) are organic chlorine compounds that were widely used as dielectrics and coolants in electrical systems in the past. They were found to be a major environmental contaminant in the 1960s. In a study, the mean PCB content at each of thirteen sites was reported for the years 1982 and 1996 (from “The ratio of DDE to PCB concentrations in Great Lakes herring gull eggs and its use in interpreting contaminants data”, Journal of Great Lakes Research...
5. Eight students were given a placement test and after a week of classes were given...
5. Eight students were given a placement test and after a week of classes were given again a placement test at the same level. Here are their scores. Before 71 78 80 90 55 65 76 77 After 75 71 89 92 61 68 80 81 (a) Test whether the scores improved after 1 week by performing a student test. (b) Test whether the scores improved after 1 week by performing a sign test.
In a study designed to test the effectiveness of acupuncture for treating migraines, 142 subjects were...
In a study designed to test the effectiveness of acupuncture for treating migraines, 142 subjects were treated with acupuncture and 80 subjects were given a sham treatment. The number of migraine attacks for the acupuncture treatment group had a mean of 1.8 and a standard deviation of 1.4. The number of migraine attacks for the sham treatment group had a mean of 1.6 standard deviation of 1.2. A - construct the 95% confidence interval estimeate of mean number of migraine...
Starch+Iodine are reacted to produce a Starch-Iodine complex. 10mL were then placed in 2 test tubes....
Starch+Iodine are reacted to produce a Starch-Iodine complex. 10mL were then placed in 2 test tubes. test tube one was heated to 80 degrees Celsius, and the result was a color change to yellow. testtube two was cooled in an ice water bath, and no change was observed. based on this, "Discuss how and why equilibrium was affected by each stress. be specific, inlcude the exothermicity/endothermicity of the rxn as it applies.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT