Question

In: Chemistry

For the Potentiometric Titration of 50.00mL of 0.1000M V2+with 0.05000M Sn4+, calculate the potential after the...

For the Potentiometric Titration of 50.00mL of 0.1000M V2+with 0.05000M Sn4+, calculate the potential after the addition of 50.00mL Sn4+ solution.

E0(Sn)= 0.15

E0(V)= -0.256

There is suffiecient data!! This problem is dealing with the equivalence point of a potentiometric titraton, all you need is the Nernst equations and the above cell potentials. I can't figure out how to set up the equation correctly, if you read this and think that there is an insufficient amount of data then please don't attempt the question because you clearly don't understand it.

Solutions

Expert Solution


Related Solutions

Calculate the pH for the titration of 40.00ml of 0.1000M solution of ethylamine (C2H5NH2) with 0.1000M...
Calculate the pH for the titration of 40.00ml of 0.1000M solution of ethylamine (C2H5NH2) with 0.1000M HCl for the following volumes of added HCl: Kb for ethylamine = 6.4X10-4 Volumes; 0.00ml; 20.00ml; 40.00ml and 50.00ml
Calculate the pH during the titration of 40.00 mL of 0.1000M propanoic acid (HPr; Ka=1.3x10-5) after...
Calculate the pH during the titration of 40.00 mL of 0.1000M propanoic acid (HPr; Ka=1.3x10-5) after adding 22.18 mL of 0.1000M NaOH. ** All volumes should have a minimum of 2 decimal places
a 25.0 ml solution of 0.1000M benzylamine (pkb= 4.67) was titrated with 0.1000M HBr. Calculate the...
a 25.0 ml solution of 0.1000M benzylamine (pkb= 4.67) was titrated with 0.1000M HBr. Calculate the pH of solution at the following volumes of added acid: 0.00ml, 5.00ml, 12.50ml, 25.00ml and 30.00ml
(50 mL of 0.02000 M KOH Titrated with 0.1000M HBr) Calculate pH after adding the following...
(50 mL of 0.02000 M KOH Titrated with 0.1000M HBr) Calculate pH after adding the following volumes of the titrant: (a) 3 mL (b) 10 mL (c) 10.5 mL Answers: (a) pH =12.12; (b) pH = 7.00; (c) pH = 3.0. I need a step-by-step explanation on how to do this.
In a potentiometric pH titration of a weak acid, why does the pH change rapidly with...
In a potentiometric pH titration of a weak acid, why does the pH change rapidly with the addition of NaOH near the endpoint but changes very slowly for pH values near the pKa of the acid?
The potentiometric titration of 25.00 mL of malonic acid C3H4O4 (pKa values 2.83 and 5.69) with...
The potentiometric titration of 25.00 mL of malonic acid C3H4O4 (pKa values 2.83 and 5.69) with 0.2217 M NaOH gave endpoints at 16.47 mL and 32.01 mL. A)Sketch the titration curve (roughly - don’t worry about exact pH values, just the general shape of the curve) and label each of the following points with the major acid or base species and the type of acid/base solution (e.g., strong acid, weak base, amphiprotic, buffer, pka values, endpoints,): i.)the beginning (before any...
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13)...
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13) after adding 25.9 mL of 0.1000M NaOH. ** All volumes should have a minimum of 2 decimal places.
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13)...
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13) after adding 28.2 mL of 0.1000M NaOH. All volumes should have 2 decimal places
Calculate the equivalence point potential for the titration of ferrous ion with dichromate ion in H2SO4
Calculate the equivalence point potential for the titration of ferrous ion with dichromate ion in H2SO4
Selective Oxidation The standard reduction potential for the half-reaction Sn4+ + 2e- --> Sn2+ is +0.15...
Selective Oxidation The standard reduction potential for the half-reaction Sn4+ + 2e- --> Sn2+ is +0.15 V. Consider data from the table of standard reduction potentials for common half-reactions, in your text. For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+. (Yes or No) 1. Sn4+ + 2e- --> Sn2+ 2. PbSO4 + 2e- --> Pb + SO42-...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT