Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13)...

Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H₃PO₄; K_a1=7.1x10^-3, K_a2=6.3x10^-8, K_a3=4.2x10^-13) after adding 25.9 mL of 0.1000M NaOH.

** All volumes should have a minimum of 2 decimal places.

Solutions

Expert Solution

pKa1 = -log Ka1

pKa1 = 2.15

millimoles of H3PO4 = 50 x 0.1 = 5

millimoles of NaOH = 25.9 x 0.1 = 2.59

H3PO4 + NaOH --------------------> NaH2PO4 + H2O

5 2.59 0 0

2.41 0 2.59 0

pH = pKa + log [NaH2PO4 / H3PO4]

pH = 2.15 + log (2.59 / 2.41)

pH = 2.18

queen_honey_blossom answered 1 year ago

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