Question
In: Chemistry
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13)...
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13) after adding 25.9 mL of 0.1000M NaOH.
** All volumes should have a minimum of 2 decimal places.
Solutions
Expert Solution
pKa1 = -log Ka1
pKa1 = 2.15
millimoles of H3PO4 = 50 x 0.1 = 5
millimoles of NaOH = 25.9 x 0.1 = 2.59
H3PO4 + NaOH --------------------> NaH2PO4 + H2O
5 2.59 0 0
2.41 0 2.59 0
pH = pKa + log [NaH2PO4 / H3PO4]
pH = 2.15 + log (2.59 / 2.41)
pH = 2.18
queen_honey_blossom answered 2 years agoRelated Solutions
Calculate the pH during the titration of 50.00 mL of 0.1000M phosphoric (H3PO4; Ka1=7.1x10-3, Ka2=6.3x10-8, Ka3=4.2x10-13)...
Calculate the pH during the titration of 50.00 mL of 0.1000M
phosphoric (H3PO4;
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All volumes should have 2 decimal places
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