Question

In: Computer Science

Once the form in this file is submitted, create a new paragraph that will stack on...

Once the form in this file is submitted, create a new paragraph that will stack on top of the existing paragraphs and will contain the data entered into the textarea. Each new paragraph should have the class 'tweet' applied to it.

*Hint: Remember to use return false; to stop the form submission from reloading the page.

<!DOCTYPE html>
<html>
<head>
   <title>Simple Twitter</title>
   <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
   <style>
   .tweet{border-top:1px solid #dedede; padding:20px;}
   </style>
   <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body class="container" style="width:50%">
   <h1>Twitter</h1>
   <form id="tweetForm" action="" method="">
       <div class="form-group">
           <textarea class="form-control tweetText" rows="3"></textarea>
       </div>
       <div class="form-group float-right">
           <input type="submit" class="tweetBtn btn btn-primary" value="Tweet">
       </div>
   </form>
   <div style="clear:both;">&nbsp;</div>
   <p class="tweet">I'm having lunch right now</p>
   <p class="tweet">This is my first Tweet!!</p>
      
</body>
</html>

It should maybe be something structure like this, not sure.

$('#eventExample').submit(function(){
                   $(this).find('input').attr('disabled', true); //find() gets an elements descendants
                   return false;
               });

Solutions

Expert Solution

Deserves thumbs up :)

<!DOCTYPE html>
<html>
<head>
<title>Simple Twitter</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
<style>
.tweet{border-top:1px solid #dedede; padding:20px;}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
</head>
<body class="container" style="width:50%">
<h1>Twitter</h1>
<form id="tweetForm" action="" method="">
<div class="form-group">
<textarea id="myInput" class="form-control tweetText" rows="3"></textarea>
</div>
<div class="form-group float-right">
<input onclick="newElement()" class="tweetBtn btn btn-primary" value="Tweet">
</div>
</form>
<div style="clear:both;">&nbsp;</div>
<div id="myUL">
<p class="tweet">I'm having lunch right now</p>
<p class="tweet">This is my first Tweet!!</p>
</div>
<script>
function newElement() {
var li = document.createElement("p");
li.setAttribute("class", "tweet");
var inputValue = document.getElementById("myInput").value;
var t = document.createTextNode(inputValue);
li.appendChild(t);
if (inputValue === '') {
alert("You must write something!");
} else {
document.getElementById("myUL").appendChild(li);
}
}
</script>
</body>
</html>

 

 

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Once the form in this file is submitted, create a new paragraph that will stack on top of the existing paragraphs and will contain the data entered into the textarea. Each new paragraph should have the class 'tweet' applied to it. *Hint: Remember to use return false; to stop the form submission from reloading the page. <!DOCTYPE html> <html> <head> <title>Simple Twitter</title> <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous"> <style> .tweet{border-top:1px solid #dedede; padding:20px;} </style> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> </head> <body class="container" style="width:50%"> <h1>Twitter</h1>...
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