Question

Assign an oxidation state to each element or ion:

Part A V Express your answer as a signed integer.

Part B Mg2+ Express your answer as a signed integer.

Part C Cr3+

Assign an oxidation state to each atom in each polyatomic ion.

Part B Express your answer as a signed integer. oxidation state of O:

Part C OH− Express your answer as a signed integer. oxidation state of O:

Part D Express your answer as a signed integer. oxidation state of H:

Part E NO3− Express your answer as a signed integer. oxidation state of N:

Part F Express your answer as a signed integer. oxidation state of O:

Part G NO2− Express your answer as a signed integer. oxidation state of N:

Part H Express your answer as a signed integer. oxidation state of O:

Part A Use oxidation states to identify the oxidizing agent and the reducing agent in the following redox reaction.

2Na(s)+2H2O(l)→2NaOH(aq)+H2(g)

Express your answer as a chemical formula. reducing agent: S

Part B Express your answer as a chemical formula. oxidizing agent:

Answer 1

oxidation state of element is = 0
oxidation state of ion = charge of ion

Part A

V: oxidation state = 0

Part B

Mg2+;; oxidation state = +2

Part C
Cr3+ :: oxidation state = +3

Part C;;
OH- :: total oxidation state = -1
oxidation state of H = +1
let x be oxidation state of O

x+ 1 + -1
x= -2
oxidation state of H = +1
oxidation state of O= -2
***************************

NO3-

oxidation state of O= -2
oxidation state of N= +5
********************************
NO2-
oxidation sate of O= -2
oxidation state of N= +3
**********************************
2Na(s)+2H2O(l)→2NaOH(aq)+H2(g)

Na oxidation state = 0
in H2O
H:: oxidation state = +1
O ;; oxidation state = -2

in NaOH
Na:: oxidation state =+1

In H2
H:: oxidation state = + 0

Na :: oxidation state increased, so it undergone oxidation[ reducing agent]
H :: oxidation state decreased, so it undergone reduction[oxidizing agent]

reducing agent = Na
oxidizing agent = H