Question

In: Chemistry

54.0 g aluminum at 50.0oC is dumped into water at 38.5oC. The water warms to 40.0oC.

 

54.0 g aluminum at 50.0oC is dumped into water at 38.5oC. The water warms to 40.0oC. 

What is specific heat capacity of aluminum?                                                                  

           a) ____________

What is molar heat capacity of aluminum?                                                                               

         b) ____________

 

When 10.0 g ammonium nitrate is dissolved in 50.0 g water at 25.0oC, the final temperature of the solution is 20.0oC.

a. What is the q of the water? (SH water = 4.20 J/g K) (10 pt)

qH2O _________

b. What is the molar change in enthalpy (ΔH in kJ/mol NH4NO3) for the solution process?

ΔH ___________

Solutions

Expert Solution

(1)

heat lost by Al = heat gained by water

mass of Al*SAl*DT = mass of water*S*DT

   54*s*(50-40) = mass of water*4.184*(40-38.5)

mass of water not given


(2)

a) q of the water = m*s*DT

                   = (50)*4.2*(25-20)

                   = 1050 joule

qH2O = 1050 joule

b. no of mol of Al(NO3)3 dissolved = 10/213 = 0.047 mol

     molar change in enthalpy (ΔH) = -q/n

                                    = -1.05/0.047

           DHrxn = -22.3 kj/mol
   

queen_honey_blossom answered 2 years ago
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