Question

In: Math

A recent survey reported that 63% of​ 18- to​ 29-year-olds in a certain country own tablets....

A recent survey reported that 63% of​ 18- to​ 29-year-olds in a certain country own tablets. Using the binomial​ distribution, complete parts​ (a) through​ (e) below.

?: .52 ?=6

a. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, four will own a​ tablet?

The probability is ____

​(Type an integer or a decimal. Round to four decimal places as​ needed.)

b. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, all six will own a​ tablet?

The probability is ____

​(Type an integer or a decimal. Round to four decimal places as​ needed.)

c. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, at least four will own a​ tablet?

The probability is ____

​(Type an integer or a decimal. Round to four decimal places as​ needed.)

d. What are the mean and standard deviation of the number of​ 18- to​29-year-olds who will own a tablet in a survey of​ six?

The mean number of​ 18- to​ 29-year-olds who own tablets out of six surveyed is _____

​(Type an integer or a decimal. Round to four decimal places as​ needed.)

The standard deviation of the number of​ 18- to​ 29-year-olds who own tablets out of six surveyed is

nothing.

​(Type an integer or a decimal. Round to four decimal places as​ needed.)

Solutions

Expert Solution

In the question the value of p is given as 63%(0.63) and in the next line value of p is given as 0.52
I will use both the values to solve the answers:
We know that X~Bin(6,0.63) or X~Bin(6,0.52)

p=0.63 or p=0.52


a)P(X=4) 4 people owning tablet.

using p=0.52

b)P(X=6)

using p=0.52

c)

P(X=4) 0.323487
P(X=5) 0.220321
P(X=6) 0.062524
total= 0.606331

Using p=0.52

P(X=4) 0.252689
P(X=5) 0.109499
P(X=6) 0.019771
total= 0.381959

d)


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