In: Math
A recent survey reported that 63% of 18- to 29-year-olds in a certain country own tablets. Using the binomial distribution, complete parts (a) through (e) below.
?: .52 ?=6
a. What is the probability that in the next six 18- to 29-year-olds surveyed, four will own a tablet?
The probability is ____
(Type an integer or a decimal. Round to four decimal places as needed.)
b. What is the probability that in the next six 18- to 29-year-olds surveyed, all six will own a tablet?
The probability is ____
(Type an integer or a decimal. Round to four decimal places as needed.)
c. What is the probability that in the next six 18- to 29-year-olds surveyed, at least four will own a tablet?
The probability is ____
(Type an integer or a decimal. Round to four decimal places as needed.)
d. What are the mean and standard deviation of the number of 18- to29-year-olds who will own a tablet in a survey of six?
The mean number of 18- to 29-year-olds who own tablets out of six surveyed is _____
(Type an integer or a decimal. Round to four decimal places as needed.)
The standard deviation of the number of 18- to 29-year-olds who own tablets out of six surveyed is
nothing.
(Type an integer or a decimal. Round to four decimal places as needed.)
In the question the value of p is given as 63%(0.63) and in the
next line value of p is given as 0.52
I will use both the values to solve the answers:
We know that X~Bin(6,0.63) or X~Bin(6,0.52)
p=0.63 or p=0.52
a)P(X=4) 4 people owning tablet.
using p=0.52
b)P(X=6)
using p=0.52
c)
P(X=4) | 0.323487 |
P(X=5) | 0.220321 |
P(X=6) | 0.062524 |
total= | 0.606331 |
Using p=0.52
P(X=4) | 0.252689 |
P(X=5) | 0.109499 |
P(X=6) | 0.019771 |
total= | 0.381959 |
d)