Question

In: Statistics and Probability

A recent survey reported that 57% to 18 to 29 year olds in a certain country...

A recent survey reported that 57% to 18 to 29 year olds in a certain country own tablets. Using the binomial distribution , complete parts a through e below.

a. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, four will own a​ tablet?

b. What is the probability that in the next six? 18- to? 29-year-olds surveyed, all six will own a? tablet?

c. What is the probability that in the next six? 18- to? 29-year-olds surveyed, at least four will own a? tablet?

d. What are the mean and standard deviation of the number of? 18- to? 29-year-olds who will own a tablet in a survey of? six?

e. What assumptions do you need to make in? (a) through? (c)? Select all that apply.

-The outcome of any observation is independent of the outcome of any other observation.

-The probability of an observation being classified as the event of? interest,

pi??, is constant from observation to observation.

-The outcome of any observation is dependent of the outcome of any other observation.

-Each observation is classified into one of two mutually exclusive and collectively exhaustive categories.

Solutions

Expert Solution

GIVEN THAT :-

According to the question we have that ,

A survey reported that 57% to 18 to 29 year olds in a certain country own tablets.

TO FIND :A)What is the probability that in the next six​ 18- to​29-year-olds surveyed, four will own a​ tablet?

now from the question we have that

n=6 ,x= 4, p= 0.57 and

q=1-p

=1-0.57

= 0.43

q=0.43

TO FIND :A)What is the probability that in the next six​ 18- to​29-year-olds surveyed, four will own a​ tablet?

for finding the P(X=4) we have a formula

P(X=4)= Ncx*p^x*q^n-x.

substituting the values and solving we get that

= 0.2928 =BINOMDIST (4,6,0.57,FALSE)

TO FIND :B) What is the probability that in the next six​ 18- to​29-year-olds surveyed, all six will own a​ tablet?

So from the above we use the same formula and the same values for finding the P(X=6)

P(X=6)= Ncx*p^x*q^n-x

= 0.0343

TO FIND :C)What is the probability that in the next six​ 18- to​29-year-olds surveyed, at least four will own a​ tablet?

So as from the above we use the formula and the same values

P(X>=4)

=1- BINOMDIST(3,6,0.57,TRUE)

= 0.48

TO FIND :D)What are the mean and standard deviation of the number of​18- to​ 29-year-olds who will own a tablet in a survey of​ six?

for finding the mean we have a formula mean =np

n=6 ;p=0.57

there fore n*p =6*0.57

mean = 3.42

now for finding the variance we have a formula variance =npq

n=6 ;p=0.57;q=0.43 from the above substituting we get that

=6*0.57*0.43

variance =1.4706

now for finding the standared deviation we have a formula = sqrt(variance)

=sqrt (1.4706) from the above

standared deviation =1.2127

I HAVE SOLVED 4 OF THEM FOR THE LAST ONEPLEASE REPOST THE QUESTION AGAIN

Please give up vote


Related Solutions

A recent survey reported that 50​% of​ 18- to​ 29-year-olds in a certain country own tablets....
A recent survey reported that 50​% of​ 18- to​ 29-year-olds in a certain country own tablets. Using the binomial​ distribution complete. c. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, at least four will own a​ tablet? The probability is_______________. d.The standard deviation of the number of? 18- to? 29-year-olds who own tablets out of six surveyed ?(Type an integer or a decimal. Round to four decimal places as? needed.) e. What assumptions do you...
A recent survey reported that 63% of​ 18- to​ 29-year-olds in a certain country own tablets....
A recent survey reported that 63% of​ 18- to​ 29-year-olds in a certain country own tablets. Using the binomial​ distribution, complete parts​ (a) through​ (e) below. ?: .52 ?=6 a. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, four will own a​ tablet? The probability is ____ ​(Type an integer or a decimal. Round to four decimal places as​ needed.) b. What is the probability that in the next six​ 18- to​ 29-year-olds surveyed, all...
21. In a survey of women in a certain country​ (ages 20−​29), the mean height was...
21. In a survey of women in a certain country​ (ages 20−​29), the mean height was 65.8 inches with a standard deviation of 2.87 inches. Answer the following questions about the specified normal distribution. ​(a) The height that represents the 95th percentile is ___. (b) What height represents the first​ quartile? 22. The weights of bags of baby carrots are normally​ distributed, with a mean of 34 ounces and a standard deviation of 0.31 ounce. Bags in the upper​ 4.5%...
in a survey of men in a certain country ages (20-29) the mean height was 64.6...
in a survey of men in a certain country ages (20-29) the mean height was 64.6 inches with a standard deviation of 2.8 inches. 1. the height that represents the 99th percentile is ?? inches (round to two decimals places as needed) 2. the height that represents the first quartile is ?? inches (round to two decimal places as needed)
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 65.6...
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 65.6 inches with a standard deviation of 2.85 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of women in a certain country​ (ages 20-​29), the mean height was 65.1...
In a survey of women in a certain country​ (ages 20-​29), the mean height was 65.1 inches with a standard deviation of 2.84 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile?
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 64.9...
In a survey of women in a certain country​ (ages 20minus​29), the mean height was 64.9 inches with a standard deviation of 2.81 inches. Answer the following questions about the specified normal distribution. ​(a) What height represents the 95th ​percentile? ​(b) What height represents the first​ quartile? ​(a) The height that represents the 95th percentile is nothing inches. ​(Round to two decimal places as​ needed.) ​(b) The height that represents the first quartile is nothing inches. ​(Round to two decimal...
As reported by a recent​ survey, the mean height of females 20 to 29 years old...
As reported by a recent​ survey, the mean height of females 20 to 29 years old is μ=63.9 inches. If the height is approximately normally distributed with σ=2.8 inches, answer the following questions. Click the icon to view a table of areas under the normal curve. ​(a) What is the percentile rank of a​ 20- to​ 29-year-old female who is 60.9 inches​ tall? ______th percentile ​(Round to the nearest integer as​ needed.) ​(b) What is the percentile rank of a​...
Question: do these data represent compelling evidence that the proportion of unemployed 18-29 year-olds that have...
Question: do these data represent compelling evidence that the proportion of unemployed 18-29 year-olds that have diabetes is di↵erent from the proportion of employed 18-29 year-olds that have diabetes? [Counts] Unemployed Employed Total Diabetes 146 717 863 No Diabetes 5709 47057 57766 Total 5855 47774 58629         (a) In the notation we are using in this course, what is the value of n2? (b) In the notation we are using in this course, what is the value of pˆ1?       ...
a survey of 2284 adults in a certain large country aged 18 and older conducted by...
a survey of 2284 adults in a certain large country aged 18 and older conducted by reputable polling organization founded that 424 have donated blood in the past two years. Complete Parts (a) through (C). a) obtain a point estimate for the population proportion of adults in the country age 18 and older who have donated blood in the past two years. b) verify that the requirements for constructing a confidence interval. the sample [ a) can be assumed to...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT