Three equal impedances, (8+j6) ohms are connected in wye across a three-phase, three-wire supply. The symmetrical...

Three equal impedances, (8+j6) ohms are connected in wye across a three-phase, three-wire supply. The symmetrical components of the phase A line voltages are:

Va0 = 0

Va1 = 220 + j 28.9 V

Va2 = -40 - j 28.9

If there is no connection between the load neutral and the supply neutral, Calculate the symmetrical currents of line a,b, and c.

Expert Solution

Manojponduru answered 8 months ago

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