In: Statistics and Probability
Does brand and location of the product increase sales? A market researcher designs an experiment to see if the brand and location of chewing gum in a grocery store has anything to do with the average volume of gum sales. Six brands of chewing gum are moved to four different locations within a store. The gum sale results can be found in the excel file ChewingGum. Run the appropriate tests and place the screen shot of your minitab or excel output below.
Run all tests at the 5% significance level. When running a chi square test for association, you MUST check off “each cell’s contribution to Chi-Square” in MiniTab (this is found by selecting “statistics” when in the test dialog box). If using Excel you must complete these by hand within excel.When running a one-way or two-way ANOVA test, also perform a Fisher’s LSD comparison test for any significant factors, at the 5% significance level.
Brand | Location | Sales |
A | Front | 150 |
B | Front | 156 |
C | Front | 203 |
D | Front | 183 |
E | Front | 147 |
F | Front | 190 |
A | Back | 58 |
B | Back | 62 |
C | Back | 89 |
D | Back | 73 |
E | Back | 46 |
F | Back | 83 |
A | Left | 111 |
B | Left | 98 |
C | Left | 117 |
D | Left | 118 |
E | Left | 101 |
F | Left | 113 |
A | Right | 130 |
B | Right | 117 |
C | Right | 105 |
D | Right | 113 |
E | Right | 114 |
F | Right | 115 |
We conduct Anova: Two Way
Factor Information
Factor Type Levels Values
Brand
Fixed 6 A, B, C, D, E, F
Location Fixed 4 Back, Front,
Left, Right
Analysis of Variance
Source DF Adj SS Adj
MS F-Value P-Value
Brand 5
2177 435.5
2.53 0.075
Location 3 32258 10752.6
62.51 0.000
Error 15
2580 172.0
Total 23 37015
Model Summary
S R-sq
R-sq(adj) R-sq(pred)
13.1157 93.03%
89.31% 82.15%
p-value of Brand = 0.075 > alpha
hence there is not significant difference in Brand
p-value of Location = 0.000 < alpha
hence there is significant difference in Location