In: Statistics and Probability
On average, 90 patrons arrive per hour at a hotel lobby (interarrival times are exponential) waiting to check in. At present there are five clerks, and patrons wait in a single line for the first available clerk. The average time for a clerk to service a patron is three minutes (exponentially distributed). Clerks earn $10 per hour, and the hotel assesses a waiting time cost of $20 for each hour that a patron waits in line. If needed, round your answers to the nearest cent. a. Compute the expected cost per hour of the current system. $ b. The hotel is considering replacing one clerk with an Automatic Clerk Machine (ACM). Management estimates that 20% of all patrons will use an ACM. An ACM takes an average of one minute to service a patron. It costs $48 per day (one day equals eight hours) to operate an ACM. Should the hotel install the ACM? Assume that all customers who are willing to use the ACM wait in a separate queue. The hotel replace the clerk with an ACM, as the total hourly cost would to $ .
Answer:
a)
Given,
To compute the expected cost per hour of the current system
λ = 90 clients/hr
μ = 20 clients/hour.
P(j ≥ 5) = .76.
At that point, Wq = P(j ≥ 5)/(100-90)
= 0.076 hours.
Expected Cost Per Hour = 10(5) + 20(90)Wq
= 50 + 1800(.076)
Expected Cost Per Hour = $186.80.
b)
Given that,
λ = 18 clients for every hour
μ = 60 clients for every hour
a M/M/4 having λ = 72 clients/hour
μ = 20 clients/hour.
Now ,
let us consider,
ACM Wq = 18 / (60 (60 - 18))
= 0.0071 hours.
Expected ACM Cost Per Hour is given as
= 6 + 20(18)Wq
= $8.57.
For M/M/4 framework P(j≥4) = .79
Wq = 0.79/8
= 0.0988.
Expected Cost Per Hour is given as below'
= 10(4) + 20(72)(0.0988)
= $182.27
In this manner with ACM all out hourly expected expense is give as follows
i.e.,
= 182.27 + 8.57
= 190.83.
Accordingly don't utilize ACM.
The inn ought not supplant the agent with an ACM, as the complete hourly expense would diminish.i.e., reduces.