Question

Consider that a single solution that is listed as 1M NaCl has a total ion concentration that is twice as large due to the chemical formula containing two ions that are dissociatedin solution:

(1 mol Na⁺ ions + 1 mol Cl^- ions)/(1 L soln) = 2 mol ions/L soln = 2M ions

A. If one adds 1.0L of a 1.0M NaCl solution to 1.0L of a 1.0M NaCl solution, then what is the concentration of NaCl? What is the total ion concentration?

B. Generalize from the previous question: if one mixes any unreactive solutions that start with the same [ions], then what happens to the [ions] in the mixture?

C. Extrapolate from the previous question: if one mixes two solutions that initially have the same concentrations of ions but some of the ions react to form an insoluble solid, then what happens to the concentration of ions in the mixture?

D. Starting with a 10.00mL solution that is 0.300 M C₅H₁₀O₅, determine the concentration of sugar at four stages of mixing with a 7.00 M C₅H₁₀O₅​. Determine the concentration of sugar after a total of 0.50mL, 5.00mL, 500mL and eventually 5.000L of 7.00 M C₅H₁₀O₅​ are added. Sketch a plot of final concentration vs. volume of the 7.00M soln. Show any asymptotes with a dashed line.

E. If one mixes two unreactive solutions together, but the solutions have different concentrations, then what are the possible trends in solute concentration as one adds more and more of one solution? As more of one is added, is there an upper or lower limit? Consisder all cases.

Answer 1

A)
Total number of moles of NaCl added = M1*V1+ M2*V2 = 1*1 + 1*1 = 2 mol
Total volume = 1+1= 2 L

Concentration of NaCl = number of moles/ volume
                                               = 2/2
                                                = 1 M

Concentration of ion = twice Concentration of NaCl = 2*1 M = 2M

B)
Ions in the misxture just adds up. So, number of ions increases.

C)
Since some ions forms precipitate, ions in the mixture decreases

D)
It has multiple parts. We are allowed to answer only 1 question at a time. You need to ask it as different question.It is an independent question

E)
Concentration of mixture = (C1*V1+ C2*V2) / (V1+V2)
where C1 --> Concentration of 1 component
V1-->volume of 1 component
C2 --> Concentration of other component
V2-->volume of other component

Concentration of mixture will be more than the concentration of component having lesser concentration

Concentration of mixture will be less than the concentration of component having greater concentration